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abruzzese [7]
2 years ago
5

Jim needs to purchase 120 ice cream cones for his school’s ice cream social. If the ice cream cones come in packs of 20, how man

y packs does he need to buy?
EXPLAIN WITH STPES (FIRST,THEN,NEXT,LAST)

ThanksQ
Mathematics
2 answers:
Flura [38]2 years ago
6 0
6 packs bro. It’s not even that hard.
Romashka [77]2 years ago
4 0

So you're trying to identify how many packs of ice cream cones Jim needs to buy if he needs 120 in total. To find this, first you have to find what number times 20 would get you 120. Then, you muitiply 6 by 20 to make sure it's 120. Once you do, you have your final answer.

Therefore, Jim needs to buy 6 packs to have a total of 120 ice cream cones.

I hope this information was of any use to you.

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Since x belongs to the first quadrant, you take the positive root (\cos x>0 for x in quadrant I). Then

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\tan x is also positive for x in quadrant I, so you take the positive root again. You're left with

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What is the length of the curve with parametric equations x = t - cos(t), y = 1 - sin(t) from t = 0 to t = π? (5 points)
zzz [600]

Answer:

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General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Parametric Differentiation

Integration

  • Integrals
  • Definite Integrals
  • Integration Constant C

Arc Length Formula [Parametric]:                                                                         \displaystyle AL = \int\limits^b_a {\sqrt{[x'(t)]^2 + [y(t)]^2}} \, dx

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle \left \{ {{x = t - cos(t)} \atop {y = 1 - sin(t)}} \right.

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<u>Step 2: Find Arc Length</u>

  1. [Parametrics] Differentiate [Basic Power Rule, Trig Differentiation]:         \displaystyle \left \{ {{x' = 1 + sin(t)} \atop {y' = -cos(t)}} \right.
  2. Substitute in variables [Arc Length Formula - Parametric]:                       \displaystyle AL = \int\limits^{\pi}_0 {\sqrt{[1 + sin(t)]^2 + [-cos(t)]^2}} \, dx
  3. [Integrand] Simplify:                                                                                       \displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx
  4. [Integral] Evaluate:                                                                                         \displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx = 4\sqrt{2}

Topic: AP Calculus BC (Calculus I + II)

Unit: Parametric Integration

Book: College Calculus 10e

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According to the question,

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For the points to lie on the parabola,

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Learn more about parabolas here:

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