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3 years ago

What function is vertically stretched by a factor of 3 and translated 4 units right from the parent function

Mathematics

2 answers:

lyudmila [28]3 years ago

5 0

Answer:

Option B is right

Step-by-step explanation:

Consider the parent function

$y=log_5 x$

When we stretch by a factor of 3 we get the transformed funciton as

$y=3log_5 x$

Next is horizontal shift to the right by 4 units

This will be done when x is replaced by x-4

Hence we get correct answer as

$y=3log_5 (x-4)$

Option B is right

Neporo4naja [7]3 years ago

4 0

<span>The <u>correct answer</u> is:

B) 3log</span>₅<span>(x-4).

Explanation<span>:

To stretch a function by a factor of 3, we multiply the function by 3. This eliminates A and D.

To translate a function 4 units right, we add -4 to the variable before anything else is applied to it; this eliminates C.

In choice B, the log function is multiplied by 3, which gives us our vertical stretch; and the x is subtracted by 4 before anything else is applied to it, so it is translated 4 units right.</span></span>

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<h3>To find the product of 42.12 and 10^3, move the decimal point in 42.12 3 places to the right because 10^3 has 3 zeros</h3>

<em><u>Solution:</u></em>

Given that,

$\text{ product of } 42.12 \text{ and } 10^3$

Which means,

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Here, the exponent of 10 is positive ( which is 3)

When the exponent is positive, we have to move the decimal point to right

When you multiply a number by a power of 10, ( 10!, 10^2, and so on ) move the decimal point of the number to the right the same number of places as the number of zeros in the power of 10

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Katyanochek1 [597]

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If you use those identities, for $\alpha=x,\ \beta=\dfrac{\pi}{2}$ , you get:

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gulaghasi [49]

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Step-by-step explanation:

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denpristay [2]

Using the properties of alternate angles, the value of x = 8 and ∠ A = 30

<h3>What are Alternate Angles?</h3>

A transversal that crosses two parallel lines produces alternate exterior angles. They form two pairs (four total angles) of alternate outside angles since they are situated "outside" the two parallel lines but on different sides of the transversal.

For the given question,

∠A=6x−18

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As, both parallel lines are intersected by a transversal,

the value of angle ∠A and ∠180 - B is same as they are alternate angles,

⇒ 6x−18 = 180 - 14x - 38

⇒ 6x + 14x = 142 + 18

⇒ 20x = 160

⇒ x = 8

∠A = 6x−18

⇒ ∠ A = 30

To learn more abut alternate angles from given link

brainly.com/question/26167358

#SPJ13

Correct question -

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