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Svetlanka [38]
3 years ago
10

What function is vertically stretched by a factor of 3 and translated 4 units right from the parent function

Mathematics
2 answers:
lyudmila [28]3 years ago
5 0

Answer:

Option B is right

Step-by-step explanation:

Consider the parent function

y=log_5 x

When we stretch by a factor of 3 we get the transformed funciton as

y=3log_5 x

Next is horizontal shift to the right by 4 units

This will be done when x is replaced by x-4

Hence we get correct answer as

y=3log_5 (x-4)

Option B is right

Neporo4naja [7]3 years ago
4 0
<span>The <u>correct answer</u> is:

B) 3log</span>₅<span>(x-4).

Explanation<span>:

To stretch a function by a factor of 3, we multiply the function by 3. This eliminates A and D.

To translate a function 4 units right, we add -4 to the variable before anything else is applied to it; this eliminates C.

In choice B, the log function is multiplied by 3, which gives us our vertical stretch; and the x is subtracted by 4 before anything else is applied to it, so it is translated 4 units right.</span></span>
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Find out the value of x in the following polygon ​with the formula
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Answer:

50

Step-by-step explanation:

ABCD is quadrilateral. Sum of all the angles in a quadrilateral is 360. This means angle ADC will be 130.

ADE is a straight line. Angle ADC and angle CDE should sum up to 180. From here we can infer that angle CDE=x is 50

6 0
4 years ago
O is the centre of the circle, EF is a tangent, angle BCE = 28°, angle ACD = 31°
andriy [413]

Answer

a. 28˚

b. 76˚

c. 104˚

d. 56˚

Step-by-step explanation

Given,

∠BCE=28°  ∠ACD=31°  &  line AB=AC .

According To the Question,

  • a. the angle between a chord and a tangent through one of the end points of the chord is equal to the angle in the alternate segment.(Alternate Segment Theorem) Thus, ∠BAC=28°

  • b. We Know The Sum Of All Angles in a triangle is 180˚, 180°-∠CAB(28°)=152° and ΔABC is an isosceles triangle, So 152°/2=76˚

        thus , ∠ABC=76° .

  • c. We know the Sum of all angles in a triangle is 180° and opposite angles in a cyclic quadrilateral(ABCD) add up to 180˚,

Thus, ∠ACD + ∠ACB = 31° + 76° ⇔ 107°

Now, ∠DCB + ∠DAB = 180°(Cyclic Quadrilateral opposite angle)

∠DAB = 180° - 107° ⇔ 73°

& We Know, ∠DAC+∠CAB=∠DAB ⇔ ∠DAC = 73° - 28° ⇔ 45°

Now, In Triangle ADC Sum of angles in a triangle is 180°

∠ADC = 180° - (31° + 45°)  ⇔  104˚

   

  • d. ∠COB = 28°×2 ⇔ 56˚ , because With the Same Arc(CB) The Angle at circumference are half of the angle at the centre  

For Diagram, Please Find in Attachment  

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

5 0
4 years ago
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