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mina [271]
3 years ago
10

Algorithm that has been coded into something that can be run by a machine.

Computers and Technology
1 answer:
hram777 [196]3 years ago
8 0
The answer is program
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Explain why there is an overlap of skills and qualities in design professions​
strojnjashka [21]

The design process is the same in all creative occupations, thus, similar skills and qualities are required. The work of an architect, Craftperson, Fine Artist, or an Interior designer is to design. Whether one occupation designs clothing and associated fashions or another one designs interiors of building, they all design. Most people who work as designers possess similar personal qualities like creativity, better communication skills, and high skill set.

6 0
3 years ago
Create a new Die object. (Refer to Die.html for documentation.)Create a loop that will iterate at least 100 times. In the loop b
hjlf

Answer:

Java code is given below

Explanation:

import java.util.Random;

class Die{

private int sides;

public Die(){

sides = 6;

}

public Die(int s){

sides = s;

}

public int Roll(){

Random r = new Random();

return r.nextInt(6)+1;

}

}

class DieRoll{

public static void main(String[] args) {

Die die = new Die();

int arr[] = new int[6];

for(int i=0; i<6; i++)

arr[i] = 0;

for(int i=0; i<100; i++){

int r = die.Roll();

arr[r-1]++;

}

for(int i=0; i<6; i++)

System.out.println((i+1)+" was rolled "+arr[i]+" times.");

}

}

8 0
3 years ago
Software, also called a(n) ____________________, consists of a series of related instructions, organized for a common purpose, t
Naddika [18.5K]
Software is also called a program or an application.
8 0
3 years ago
When formatting numbers with the Comma Number Format tool, the numbers are formatted with _________.
irina [24]

Answer:

2 decimal places

Explanation:

5 0
3 years ago
(20 points) Given a collection of n nuts and a collection of n bolts, arranged in an increasing order of size, give an O(n) time
Blababa [14]

Answer:

Check the explanation

Explanation:

Keep two iterators, i (for nuts array) and j (for bolts array).

while(i < n and j < n) {

if nuts[i] == bolts[j] {

We have a case where sizes match, output/return

}

else if nuts[i] < bolts[j] {

what this means is that the size of nut is lesser than that of bolt and we should go to the next bigger nut, i.e., i+=1

}

else {

what this means is that the size of bolt is lesser than that of nut and we should go to the next bigger bolt, i.e., j+=1

}

}

Since we go to each index in both the array only once, the algorithm take O(n) time.

6 0
3 years ago
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