F(x)·g(x) = (3x +4)·(5 -x) = -3x^2 +11x +20
(f·g)(x) = -3x^2 +11x +20
Answer:
B
Step-by-step explanation:
The "value" of a function is the y-value.
Since we want negative y values, we look at "WHERE" the function is "UNDER" the y-axis.
Looking closely, it looks that function (the dip) is from x = -1 to x = 3
Hence, the function is negative at the interval -1 ≤ x ≤ 3
B is correct.
Is their a picture for the problem
All real numbers is the answer
