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aliya0001 [1]
3 years ago
10

The book fair had a sale where 6 books were $43.50. If you wanted to buy 2 books, how much money would you need

Mathematics
2 answers:
Masteriza [31]3 years ago
8 0
$14.50 your welcome girl
Minchanka [31]3 years ago
4 0

Answer:

$14.50

Step-by-step explanation:

you take $43.50 ( the total of all books) divide by 6 ( number of books) and you get $7.25 for each book. then you multiply by 2 because that's the ampunt of bookd the person wants. PLEASE MAKE ME BRAINLEIST ANSWER.

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30 points and brainlest if u can solve this ASAP
gizmo_the_mogwai [7]

Answer:

£265.10

Step-by-step explanation:

200+33.60+31.50=£265.10

  • <em>42×</em><u>8=336=10%=33.60</u>
  • <u>15×14=210=15%=31.50</u>
3 0
3 years ago
Read 2 more answers
In converting 30 pounds to ounces, what unit (omit the number) would you
gladu [14]

Step-by-step explanation:

to convert pounds into ounces you'd

actually multiply 16 by 30:

30 * 16

you're doing this because if one pound equals 16 ounces, if you have 30 pounds then you must've had more ounces. therefore you'd multiply.

which is 480 pounds

Enjoy!

6 0
3 years ago
The area of the top face of a cube is 49cm^3. What is the volume of th cube?​
Vlad1618 [11]

Answer:

V=2401cm^{3}

Step-by-step explanation:

The fact that the figure is a cube means all sides, faces, and corners are equal.

V=BHW

V=49cm^{2}(W)

V=49cm^{2}(49cm)\\ V=2401cm^{3}

3 0
3 years ago
What is the difference of 35- (-8)
Dennis_Churaev [7]

35-(-8)=35+8=43

~~~~~~~~

6 0
3 years ago
Read 2 more answers
According to the National Vital Statistics, full-term babies' birth weights are Normally distributed with a mean of 7.5 pounds a
Sav [38]

Answer:

68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 7.5, \sigma = 1.1

What is the probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds

This is the pvalue of Z when X = 8.6 subtracted by the pvalue of Z when X = 6.4. So

X = 8.6

Z = \frac{X - \mu}{\sigma}

Z = \frac{8.6 - 7.5}{1.1}

Z = 1

Z = 1 has a pvalue of 0.8413

X = 6.4

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.4 - 7.5}{1.1}

Z = -1

Z = -1 has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds

6 0
3 years ago
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