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3 years ago

What is the volume of the square pyramid? Round to the nearest tenth.

Mathematics

1 answer:

Shkiper50 [21]3 years ago

4 0

Answer:

1670.8 cm³

Step-by-step explanation:

Volume of square Pyramid = ⅓*a²*h

h = 15.3 cm

a = 18.1 cm

Plug in the values

Volume of the pyramid = ⅓*18.1²*15.3

Volume = 1670.81 ≈ 1670.8 cm³ (nearest tenth)

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Marcus is running a science experiment in which he measures the rate at which bacteria multiply. Every 15 seconds the bacteria d

lesantik [10]

Answer:

C. 20480

Step-by-step explanation:

so the equation is (60x3) divided by 15 because there are 3 minutes and 60 seconds in each minute and the bacteria doubles every 15 seconds so when you get your answer (12) that is how many times you will double 5.

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3 years ago

IF THREE DIAGONALS ARE DRAWN INSIDE A HEXAGON WITH EACH ONE PASSING THROUGH THE CENTER POINT OF THE HEXAGON, HOW MANY TRIANGLES

frosja888 [35]

Answer: 6 triangles

Step-by-step explanation:

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3 0

1 year ago

find the roots of the quadratic equation x^2-6x+k=0.giventhat one root is three times the other and that k is a constant.Also fi

arlik [135]

$x_{1} = 3x_{2} \\ x_{1} - 3x_{2} = 0 ←relation \: 1\\ x_{1} + x_{2} = 6 ←relation \: 2$

$(x_{1},x_{2}) : (4.5,1.5)$

$k = x_{1}x_{2} = 4.5 \times 1.5 = 6.75$

7 0

1 year ago

For the school concert band performance student tickets cost eight dollars each and adult tickets cost $12 each the seller is co

Alexxandr [17]

S + a = 300...s = 300 - a
8s + 12a = 3200

8(300 - a) + 12a = 3200
2400 - 8a + 12a = 3200
-8a + 12a = 3200 - 2400
4a = 800
a = 800/4
a = 200 <==== 200 adult tickets

s = 300 - a
s = 300 - 200
s = 100 <=== 100 student tickets

8 0

3 years ago

How much must be added to each of the three numbers 1, 11, and 23 so that together they form a geometric progression?

Sliva [168]

Answer:

Step-by-step explanation:

Let x be unknown number which should be added to numbers 1, 11, 23 to get geometric progression. Then numbers 1 + x, 11 + x, 23 + x are first three terms of geometric progression.

Hence,

$b_1=1+x\\ \\b_2=11+x\\ \\b_3=23+x$

and

$b_2=b_1\cdot q\Rightarrow 11+x=(1+x)q\\ \\b_3=b_2\cdot q\Rightarrow 23+x=(11+x)q$

Express q:

$q=\dfrac{11+x}{1+x}=\dfrac{23+x}{11+x}$

Solve this equation. Cross multiply:

$(11+x)^2=(1+x)(23+x)\\ \\121+22x+x^2=23+x+23x+x^2\\ \\121+22x=23+24x\\ \\22x-24x=23-121\\ \\-2x=-98\\ \\2x=98\\ \\x=49$

5 0

3 years ago