Answer:
Answer:
safe speed for the larger radius track u= √2 v
Explanation:
The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.
Also given that r_1= smaller radius
r_2= larger radius curve
r_2= 2r_1..............i
let u be the speed of larger radius curve
now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=
r
1
mv
2
=
r
2
mu
2
................ii
form i and ii we can write
v^2= \frac{1}{2} u^2v
2
=
2
1
u
2
⇒u= √2 v
therefore, safe speed for the larger radius track u= √2 v
The graph of f^-1 (x) is
called the inverse function of f (x). The relationship between the two is that the
point (x,y) is on the graph of f (x) if and only if the point (y,x) is on the
graph of f^-1 (x).
This means that if the point
(2, 7) is on f (x), therefore the point (7, 2) is on f^-1 (x).
<span>Answer: (7, 2)</span>
Answer:
-693.43957
Step-by-step explanation:
-3.7^5
Answer:
The answer is: 1 43/48
~hope this answered your question correctly, have a gr8 day my friend!~
Step-by-step explanation:
Answer:
$36
Step-by-step explanation:
I = prt
I = 480(.015)(5)
I = 36
