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Alexeev081 [22]
3 years ago
6

It is necessary for an automobile producer to estimate the number of miles per gallon achieved by its cars. Suppose that the sam

ple mean for a random sample of 100 cars is 27.2 miles and assume the standard deviation is 2.4 miles. Now suppose the car producer wants to test the hypothesis that μ, the mean number of miles per gallon, is 25.9 against the alternative hypothesis that it is not 25.9. Conduct a test using α=.05 by giving the following:
Mathematics
1 answer:
olga nikolaevna [1]3 years ago
7 0

Answer:

Step-by-step explanation:

Given that the sample mean for a random sample of 100 cars is 27.2 miles and assume the standard deviation is 2.4 miles.

H0: x bar = 25.9

Ha: x bar ≠ 25.9

(Two tailed test at 95% confidence)

Alpha =0.05

The hypothetical mean is 25.900  

The actual mean is 27.200  

The difference between these two values is 1.300  

The   95% confidence interval of this difference:  

From -3.462 to 6.062

t = 0.5417  

 df = 99  

 standard error of difference = 2.400

The two-tailed P value equals 0.5893  

 Since p >0.05 this difference is considered to be not statistically significant.  

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Answer:

y=2x+1

Step-by-step explanation:

First you have to find the slope:

5-1/2 so 4/2 or 2

Then you write it in point-slope: (I used the point (0,1))

y-1=2x

Simplify than:

y=2x+1

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4(9a - 4)

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4(9a - 4)

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Uppose that x is a bernoulli trial with p = .30. determine the mean of x.
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3 years ago
Amy is pulling a wagon with a force of 30 pounds up a hill at an angle of 25°. Give the force exerted on the wagon as a vector a
Fofino [41]

Answer:

Vector (ordered pair - rectangular form)

\vec F = (27.189,12.679)\,[lbf]

Vector (ordered pair - polar form)

\vec F = (30\,lbf, 25^{\circ})

Sum of vectorial components (linear combination)

\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]

Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force (\vec F), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

\vec F =  \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right) (1)

Vector (ordered pair - polar form)

\vec F = \left(\|\vec F\|, \theta\right)

Sum of vectorial components (linear combination)

\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j} (2)

Where:

\|\vec F\| - Norm of the vector force, in newtons.

\theta - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

\hat{i}, \hat{j} - Orthogonal axes, no unit.

If we know that \|\vec F\| = 30\,lbf and \theta = 25^{\circ}, then the force exerted on the wagon is:

Vector (ordered pair - rectangular form)

\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf]

\vec F = (27.189,12.679)\,[lbf]

Vector (ordered pair - polar form)

\vec F = (30\,lbf, 25^{\circ})

Sum of vectorial components (linear combination)

\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N]

\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]

8 0
2 years ago
I need help rn please​
nirvana33 [79]

Hello!

\large\boxed{\text{ slope = -3}}

Use the slope formula to solve for the slope of the line (m):

m = \frac{y^{2} -y^{1} }{x^{2} -x^{1} }

We can plug in the points (0, 4) and (1, 1) to solve:

m = \frac{1-4}{1-0}= \frac{-3}{1}  = -3

Therefore, the slope of the line is -3.

8 0
3 years ago
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