Answer:
a+9 = b
Step-by-step explanation:
a=b-9
Add 9 to each side
a+9=b-9+9
a+9 = b
24 is the answer to two ten's and four ones.
Answer:
-14
Step-by-step explanation:
I think Also 9 is wrong
This looks like an exercise that's building toward the idea of a derivative.
These calculations are done best with a calculator, but here's how the first interval is used:
Average velocity = (position at 2 - position at 1) / (2 - 1) It's really distance divided by time!
Position at t = 2:
Position at t = 1:
So over the interval [1, 2] the average velocity is
I used a spreadsheet to calculate the average velocity over the other intervals and a couple of shorter ones, too. (See attached image.)
As these intervals get shorter (the right endpoint is approaching 1), the average velocity gets closer and closer to the instantaneous velocity. An estimate would be -12.6.
Ok, I'm going to start off saying there is probably an easier way of doing this that's right in front of my face, but I can't see it so I'm going to use Heron's formula, which is A=√[s(s-a)(s-b)(s-c)] where A is the area, s is the semiperimeter (half of the perimeter), and a, b, and c are the side lengths.
Substitute the known values into the formula:
x√10=√{[(x+x+1+2x-1)/2][({x+x+1+2x-1}/2)-x][({x+x+1+2x-1}/2)-(x+1)][({x+x+1+2x-1}/2)-(2x-1)]}
Simplify:
<span>x√10=√{[4x/2][(4x/2)-x][(4x/2)-(x+1)][(4x/2)-(2x-1)]}</span>
<span>x√10=√[2x(2x-x)(2x-x-1)(2x-2x+1)]</span>
<span>x√10=√[2x(x)(x-1)(1)]</span>
<span>x√10=√[2x²(x-1)]</span>
<span>x√10=√(2x³-2x²)</span>
<span>10x²=2x³-2x²</span>
<span>2x³-12x²=0</span>
<span>2x²(x-6)=0</span>
<span>2x²=0 or x-6=0</span>
<span>x=0 or x=6</span>
<span>Therefore, x=6 (you can't have a length of 0).</span>