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Nadya [2.5K]
2 years ago
14

Rafael goes to a football game that starts at a quarter to 4. The game is 2 hours and 30 minutes long. What time does the game e

nd?
Mathematics
1 answer:
faltersainse [42]2 years ago
5 0

First lets understand what a quarter to 4 is, a quarter to 4 is 15 minutes before the stated hour. This mean it is currently 3:45.

3:45 + 30 minutes = 4:15

4:15 + 2 hours = 6:15.

The game ends at 6:15

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If two marbles are randomly selected from the bag without replacement, what is the probability that the first marble is blue?
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Answer:1,0.5, or 0 it depends

Explanation:

The probability that one event occurred depends on the total of random event, being 1 the most of the probabilities

If the two marbles are blue the probability to select a marble blue is 1

If one of the marbles is blue and the other marble is of any color the probability to select the blue marbles is:

P=1 - 1/2=1/2

Being 1/2 or 0.5 the answer

If any of the marbles are blue then the probabilities are 0

8 0
3 years ago
Fill in the box with the appropriate measure.<br> quick please I have only a few min left
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Step-by-step explanation:

first box on the left

r=4

d=8

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area = π*4*4= 16π

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d=6

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circumference= 2π*3= 6π

area =π*3*3= 9π

third box on the left

A=36π

A=36πarea= π*r*r

A=36πarea= π*r*rr= 6

A=36πarea= π*r*rr= 6d=12

A=36πarea= π*r*rr= 6d=12circumference= 2π*6= 12 π

the last box

C=18π

C=18πC= 2π*r

C=18πC= 2π*rr= 9

C=18πC= 2π*rr= 9d=18

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8 0
2 years ago
Plls help im failing
allsm [11]

Answer:

9^35

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
How many squares are on the chessboard
natka813 [3]
64
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4 0
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How many solutions does the following equation have? ln(x2 + 4x − 5) = 0
lisov135 [29]
Alrighty
remember
log_a(b)=c means a^c=b
and
ln(x)=log_e(x)
and
x^0=1 for all real values of x
so

ln(x^2+4x-5)=0 means
log_e(x^2+4x-5)=0 means
e^0=x^2+4x-5 which simplifies to
1=x²+4x-5
minus 1 both sides
0=x²+4x-6
use quadratic formula or complete the square
x=-2+\sqrt{10} and x=-2-\sqrt{10}
2 solutions
7 0
3 years ago
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