Answer:
g(x) = a(x - 23)(x + 4)
Step-by-step explanation:
Weren't there possible answer choices to share?
if this function has zeros at 23 and -4, then the function has the following form:
g(x) = a(x - 23)(x + 4)
Answer:
Quadrant IV
Step-by-step explanation:
(+, +) -> Quadrant I
(-, +) -> Quadrant II
(-, -) -> Quadrant III
(+, -) -> Quadrant IV
Answer:
<h3>37.5m/s</h3>
Step-by-step explanation:
If a coal train in Montana starts from rest and accelerates at 2.5 m/s2 for 15s,let us calculate the final velocity of the train.
Use the equation of motion v = u + at where;
v is the final velocity
u is the initial velocity = 0m/s (starts from rest)
a is the acceleration = 2.5m/s²
t is the time = 15secs
Substituting the given parameters into the formula;
v = 0+(2.5)(15)
v = 0+37.5
v = 37.5m/s
Hence the final velocity of the train is 37.5m/s
Answer: 6 x 10^12
Step-by-step explanation:
Move the decimal to the left so there is one non-zero digit number left of the decimal point. This will be the exponent placed on 10
