Am irrational number is a number that cannot be expressed as a fraction for any integers. numbers of the form,where is the logarithm, are irrational if and are integers, one of which has a prime factor which the other lacks. is irrational for rational
Answer:
f(x) = 2x^2 - 3x + 1
Step-by-step explanation:
The root 1 is associated with the factor (x - 1).
The root 1/2 is associated with the factor (x - 1/2), which in turn is equivalent to (2x -1)
The quadratic in question is f(x) = (x - 1)(2x - 1). To write this in standard form, perform the indicated multiplication:
f(x) = 2x^2 - 2x - x + 1, or f(x) = 2x^2 - 3x + 1
the question does not present the options, but this does not interfere with the resolution
we know that
if a and b are parallel lines
so
1) m∠2=58°------> by corresponding angles
2) m∠1=4x-10------> by alternate exterior angles
3) [m∠2+m∠(3x-1)]+m ∠1=180°------> by supplementary angles
58+(3x-1)+4x-10=180
7x=180-47
7x=133
x=19°
4) angle (4x-10)=-4*19-10-------> 66°
5) angle 3x-1=3*19-1-------> 56°
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How many jumps is it from the decimal point to the position to the right of the 6
The answer to that is 3 jumps. Since the move of the decimal made the number larger than it really is, it will take a negative value to put it back where it belongs.
So A) is the correct answer. It is in scientific notation and if you move the decimal back 3 place you get the number you stared with.
