Solve the problem.
1 answer:
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The graphs arey=(1/3)x^2
and y=3
they intersect at x=3
so the limits are x=0 and 3
to rotate it about y=k, minus k from every function
which evaluates to 72/5pi
A is asnwer
and y=3
they intersect at x=3
so the limits are x=0 and 3
to rotate it about y=k, minus k from every function
which evaluates to 72/5pi
A is asnwer