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Mumz [18]
3 years ago
10

The average of an electrician's hourly wage and a plumber's hourly wage is $33. One day a contractor hires an electrician for 7h

r of work and the plumber for 4hr of work and pays a total of $396 in wages. Find the hourly wage for the electrician and for the plumber.

Mathematics
1 answer:
Leno4ka [110]3 years ago
7 0

Answer:

Electrician = 44

Plumber = 22

Step-by-step explanation:

Let :

Electrician Hourly wage = x

Plumber's hourly wage = y

Average = 33

(x + y ) /2 = 33

x + y = 66 - - - - (1)

7x + 4y = 396 - - - (2)

From (1)

x = 66 - y

Put x = 66 - y in (2)

7(66-y) + 4y = 396

462 - 7y + 4y = 396

-3y = - 66

y = 22

x = 66 - 22

x = 44

Electrician = 44

Plumber = 22

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Step-by-step explanation:

N=km

72=k×48

72=48k

k=72/48

k=1.5

N=1.5m

N=1.5×144

N=216

3 0
2 years ago
Find two consecutive whole numbers such that 4/7 of the larger exceeds 1/2 of the smaller by 5
Darina [25.2K]

Answer:

The consecutive numbers are 62 and 63

Step-by-step explanation:

Let the larger number be represented by x and the smaller number by y,

Provided they are consecutive numbers;

x = y + 1 --- Equation 1

From the question; we have that

\frac{4x}{7} = \frac{y}{2} + 5 --- Equation 2

Required

Find x and y

Multiply both sides of equation 2 by 14

14 * \frac{4x}{7} = 14 * \frac{y}{2} + 14 * 5

2 * 4x = 7 * y + 70

8x = 7y + 70 ---- Equation 3

Substitute y + 1 for x in equation 2

8(y + 1) = 7y + 70

Open bracket

8y + 8 = 7y + 70

Collect like terms

8y - 7y = 70 - 8

y = 62

x = y + 1

So,

x = 62 + 1

x = 63

Hence, the consecutive numbers are 62 and 63

8 0
3 years ago
(2x - 1)<br> (4x + 28)°
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Using the knowledge i know i think this is the right answer

Have a great day :)

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Step-by-step explanation:

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