All categories

3 years ago

How do I do this? please help Im stuck on this and I cant understand the concept.

Mathematics

1 answer:

miskamm [114]3 years ago

6 0

Answer:

take the total number of all x variables

You might be interested in

Evaluate x-y if x=-11 and y=26*

RUDIKE [14]

The answer iss -37.

8 0

3 years ago

Read 2 more answers

If 3 pounds of apples costs $7.50, what is the unit rate for cost per pound? What will 9 pounds cost?

inna [77]

Answer:per pound would cost 2.50 and for nine pounds it would cost 22 dollars and 50 cent

Step-by-step explanation:

750 divided by 3=250 just add your point were before five and 7.50 plus 7.50 equals 15 plus 7.50 equals 22.50

3 0

3 years ago

Evaluate the expression. 5^2−4⋅6+11 Enter your answer in the box.

mart [117]

Explanation:

This question's it's about the order of operations. P-parenthesis, E-exponents, M-multiply, D-divide, A-add, and S-subtract. It can also go left to right.

Do exponents first.

$5^2=5*5=25$

$25-4*6+11$

Then, multiply left to right.

$4*6=24$

$25-24+11$

And add/subtract left to right.

$25-24=1$

$1+11=12$

$\boxed{=12}$

Hope this helps!

Thanks!

Have a great day!

6 0

2 years ago

!PLEASE HELP!<br>Solve for MN. <br><br>A) 21 <br><br>B)9 <br><br>C)6 <br><br>D)4

Oksanka [162]

The measure of MN from the diagram is 6

<h3>Similarity theorem of triangles</h3>

From the given triangle, the expression below is true;

ML/LK = MN/NO

Given the following parameters

ML = 4

LK = 10

NO= 15

Substitute the given parameters into the formula

4/10 = MN/15

Cross multiply

10MN = 4 * 15

10MN = 60

MN = 6

Hence the measure of MN from the diagram is 6

Learn more on similar triangles here: brainly.com/question/14285697

7 0

2 years ago

Suppose that surface σ is parameterized by r(u,v)=⟨ucos(3v),usin(3v),v⟩, 0≤u≤7 and 0≤v≤2π3 and f(x,y,z)=x2+y2+z2. Set up the sur

Bad White [126]

Looks like you have most of the details already, but you're missing one crucial piece.

$\sigma$ is parameterized by

$\vec r(u,v)=\langle u\cos3v,u\sin3v,v\rangle$

for $0\le u\le7$ and $0\le v\le\frac{2\pi}3$ , and a normal vector to this surface is

$\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\left\langle\sin3v,-\cos3v,3u\right\rangle$

with norm

$\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=\sqrt{\sin^23v+(-\cos3v)^2+(3u)^2}=\sqrt{9u^2+1}$

So the integral of $f(x,y,z)=x^2+y^2+z^2$ is

$\displaystyle\iint_\sigma f(x,y,z)\,\mathrm dA=\boxed{\int_0^{2\pi/3}\int_0^7(u^2+v^2)\sqrt{9u^2+1}\,\mathrm du\,\mathrm dv}$

6 0

2 years ago