All categories

3 years ago

How do I do this? please help Im stuck on this and I cant understand the concept.

Mathematics

1 answer:

miskamm [114]3 years ago

6 0

Answer:

take the total number of all x variables

You might be interested in

Determine the measure of an angle that is three-fourths of a full turn.

Agata [3.3K]

Answer:

270

Step-by-step explanation:

6 0

2 years ago

Precal help if you could could you answer both. Me finishing this helps me graduate.

oee [108]

Exercise 1:

The easiest way to compute powers of complex numbers is to write them in the form

$z = \rho e^{i\theta} = \rho(\cos(\theta)+i\sin(\theta))$

In this form, you have

$z^n = \rho^n e^{in\theta} = \rho^n(\cos(n\theta)+i\sin(n\theta))$

The magnitude of the number is given by

$z=a+bi \implies \rho = \sqrt{a^2+b^2}$

So, we have

$z=-1+\sqrt{3}i \implies \rho = \sqrt{1+3}=2$

As for the angle, we have

$z=a+bi \implies \theta = \text{atan2}\dfrac{b}{a}$

So, we have

$z=-1+\sqrt{3}i \implies \theta = \text{atan2}\left(\dfrac{-\sqrt{3}}{-1}\right) = -\dfrac{2\pi}{3}$

Finally,

$z=-1-\sqrt{3}i = 2\left(\cos\left( -\dfrac{2\pi}{3}\right) + i\sin\left( -\dfrac{2\pi}{3}\right)\right) \implies z^6 = 2^6\left(\cos\left( -4\pi\right) + i\sin\left(-4\pi\right)\right) = 64$

Exercise 2:

You simply have to compute the trigonometric function:

$\cos\left(-\dfrac{\pi}{4}\right) = \dfrac{\sqrt{2}}{2},\quad \sin\left(-\dfrac{\pi}{4}\right) = -\dfrac{\sqrt{2}}{2}$

So, we have

$z = \sqrt{2}\left(\dfrac{\sqrt{2}}{2} - i\dfrac{\sqrt{2}}{2}\right) = 1-i$

7 0

3 years ago

Write 0.728 as a percent and as a simplified fraction.

Lisa [10]

Answer:

91 /125

Step-by-step explanation:

8 0

3 years ago

Which statement be describes the rotation ?

soldi70 [24.7K]

counterclockwise 90 degrees

7 0

2 years ago

Read 2 more answers

100 points !!!!!!! PLZ HELP

Olenka [21]

Answer:1. -6 ≤ x < -1 . . . . conjunction

2. x ≤ 6 . . or . . 10 ≤ x . . . . disjunction

3. 7 ≤ x < 12 . . . . conjunction

4. x < -9 . . or . . -3 ≤ x . . . . disjunction

5. 2 ≤ x ≤ 5 . . . . conjunction

6. x ≤ 54 . . or . . 66 ≤ x . . . . disjunction

7. 39 < x ≤ 43 . . . . conjunction

Step-by-step explanation:

I'm assuming its "Pattern". This is because its in a pattern of "Conjunction, Disjunction, Conjunction, Disjunction, etc." and theres 7 letters in the word Pattern.

Usually a problem with this wording will have a list of numbers with letter designators. You find the number that is in the solution set and the corresponding letter is part of the "secret word

6 0

3 years ago

Read 2 more answers