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ahrayia [7]
3 years ago
5

It is 2 am help a x*y=11 but x+y=12 what is x and what is y

Mathematics
1 answer:
Troyanec [42]3 years ago
7 0

Answer:

x= 11

y= 1

#CarryOnLearning

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Number 4. will be a. because if you do 7*9=63*10=630.
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Rearrange the following and ad .005, 2,002.181, 795.41, 14.0,184
xz_007 [3.2K]

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1 2 3 4

Step-by-step explanation:

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Find f. f ″(x) = x^−2, x > 0, f(1) = 0, f(6) = 0
marin [14]

If you do in fact mean f(1)=f(6)=0 (as opposed to one of these being the derivative of f at some point), then integrating twice gives

f''(x) = -\dfrac1{x^2}

f'(x) = \displaystyle -\int \frac{dx}{x^2} = \frac1x + C_1

f(x) = \displaystyle \int \left(\frac1x + C_1\right) \, dx = \ln|x| + C_1x + C_2

From the initial conditions, we find

f(1) = \ln|1| + C_1 + C_2 = 0 \implies C_1 + C_2 = 0

f(6) = \ln|6| + 6C_1 + C_2 = 0 \implies 6C_1 + C_2 = -\ln(6)

Eliminating C_2, we get

(C_1 + C_2) - (6C_1 + C_2) = 0 - (-\ln(6))

-5C_1 = \ln(6)

C_1 = -\dfrac{\ln(6)}5 = -\ln\left(\sqrt[5]{6}\right) \implies C_2 = \ln\left(\sqrt[5]{6}\right)

Then

\boxed{f(x) = \ln|x| - \ln\left(\sqrt[5]{6}\right)\,x + \ln\left(\sqrt[5]{6}\right)}

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2 years ago
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sergeinik [125]

Answer:

The line is ;

4y = -x + 56

or

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Generally, the equation of a straight line is;

y = mx + c

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so for y = 4x - 6

The slope is 4

If two lines are perpendicular, the product of their slopes is -1

So for the second line, the slope will be -1/4

The equation in the point slope format will be ;

y-12 = -1/4(x-8)

y-12 = -x/4 + 2

Multiply through by 4

4y-48 = -x + 8

4y = -x + 8 + 48

4y = - x + 56

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3 years ago
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