Question

Side A of a triangle is twice side B. Side C is 2m shorter than side A. The perimeter is 98m. Find the length of each side. This is what is was working on, but at the end, when I added up the sides, they did not equal 98m. A + B + C = Perimeter A= 2B, B= B, C= A-2 or 2B - 2 2B + B + 2B - 2 = 98 5B = 100 B = 25m Therefore, 98 = 50 + 25 + 48, but it doesn't A B C Can you explain, please? A B C

Answer 1

A=2B
B=B
C=A-2=2B-2

A+B+C=98
5B-2=98
5B=100
B=20

Thus A= 2B = 40
C=38

Nothing much wrong only calculation mistakes