Answer:
The short answer is there isn’t.
Start by writing each of these as an expression:
x * y = 60
x + y = 7
Next, solve each for the same variable; in this case, y:
(x * y) / x = 60 / x
.: y = 60 / x
(x + y) - x = 7 - x
.: y = 7 - x
Next, replace y of the second expression to the first
y = 60 / x & y = 7 - x
.: 7 - x = 60 / x
Now, solve for x:
(7 - x) * x = (60 / x) * x
.: x * 7 - x^2 = 60
This is quadratic, so write it in the form of ax2 + bx + x = 0
(-1)x^2 + (7)x + (-60) = 0
.: a = -1, b = 7, c = -60
Finally solve for b:
x = (-b +- sqrt(b^2 - 4*a*c)) / 2a
.: x = (-7 +- sqrt(7^2 - 4*-1*-60)) / (2 * -1)
.: x = (-7 +- sqrt(49 - 240)) / -2
.: x = (-7 +- sqrt(-191)) / -2
The square root of a negative value is imaginary and thus there’s no real answer to this problem.
The word that describes it is congruent
Answer:
-28 + -1 = -29
-14 + -2 = -16
-7 + -4 = -11
-4 + -7 = -11
-2 + -14 = -16
-1 + -28 = -29
1 + 28 = 29
2 + 14 = 16
4 + 7 = 11
7 + 4 = 11
14 + 2 = 16
28 + 1 = 29
Step-by-step explanation:
r - 4/5r = 1/5r + 1
Subtract 1/5r from each side: r - 4/5r - 1/5r = 1
Combine all the 'r' terms on the left side:
r - 5/5r = 1
r - r = 1
0 = 1
There is no value of 'r' that can make ' 0 = 1 ' a true statement.
So the equation has <em>no solution</em>.
The answers should be: (-2,5), (-2,-2), (-6,-1), (2,1)
Hope this helped :)
