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bazaltina [42]
2 years ago
9

I need help like now

Mathematics
1 answer:
snow_tiger [21]2 years ago
8 0
Are you trying to find x?
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What is the slops of the line that passes through the pair of points? (-5.5, 6.1), (-2.5, 3.1)
Svetach [21]

Answer:

most graphs don't go passed 10 so it's undefined

Step-by-step explanation:


8 0
2 years ago
Please help me its geometry ​
Stels [109]

Answer:

helikopter hi do you want in sex

8 0
2 years ago
7 copper spheres with radii of 4
Anit [1.1K]

We will see that the cube must be 10.23 inches tall.

<h3>How tall is the cube?</h3>

The volume of the cube must be equal to the volume of the 4 spheres. Remember that the volume of a sphere of radius R is:

V = (4/3)*3.14*R^3

In this case, the radius is 4 inches, so we can write:

V = (4/3)*3.14*(4 in)^3 = 267.95 in^3

Then the volume of the 4 spheres is:

4*267.95 in^3 = 1,071.79 in^3

The volume of a cube of side length S is given by:

V = S^3

Then we must have:

S^3 = 1,071.79 in^3

S = ∛(1,071.79 in^3) = 10.23 in

We conclude that the cube is 10.23 inches tall.

If you want to learn more about spheres, you can read:

brainly.com/question/10171109

6 0
2 years ago
Why are 1 4 9 16 and 25 called perfect squares
olga nikolaevna [1]
Perfect squares can be divided and multiplied by the same number to get the same number. For example 25/5=5. 5*5=25.
4/2=2, 2*2=4
1/1=1, 1*1=1
9/3=3, 3*3=9
16/4=4, 4*4=16.
Hence the perfect squares.
4 0
3 years ago
Read 2 more answers
A student wants to determine the coefficients of static friction and kinetic friction between a box and a plank. She places the
Arturiano [62]

Answer:

the coefficients of static friction is 0.577

the coefficients of fkinetic friction is 0.54

Step-by-step explanation:

given information

θ = 30°

S = 2.5 m

t = 4 s

- Static friction

F - F(friction) = 0

W sin θ = μs W cos θ  

μs = sin θ/ cosθ

   = tan θ

   = tan 30°

   = 0.577

- kinetic friction

S = v_{0} t + \frac{1}{2} at^{2}

v_{0} t = 0

S = \frac{1}{2} at^{2}

a = \frac{2S}{T^{2} } = \frac{2 x 2.5}{4^{2} }

  = 0.3 m/s^{2}

F - F(friction) = m a

W sin θ - μ W cos θ  = m a

mg sin θ - μk mg cos θ  = m a

g sin θ - μk g cos θ  = a

μk = g sin θ  - a / g cos θ

    = 9.8 sin 30° - 0.3 / 9.8 cos 30°

    = 0.54

7 0
3 years ago
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