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iren2701 [21]
3 years ago
14

Jake's test scores are 86, 70, 72, 100, 96, and 80. What must Jake earn of his last test to earn a mean grade of exactly 85%?

Mathematics
1 answer:
kompoz [17]3 years ago
4 0

Answer:

91

Step-by-step explanation:

Mean is calculated as

mean = \frac{sum}{count}

let x be his test score of his last test , then

\frac{86+70+72+100+96+80+x}{7} = 85 ( multiply both sides by 7 )

504 + x = 595 ( subtract 504 from both sides )

x = 91

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Answer:

Two real world situations are shown below.

Step-by-step explanation:

Initial population of a certain bacteria is 1 thousand and the population doubles in each hour. So, population of bacteria (in thousands) after x hours is

f(x)=1(2)^x

f(x)=(2)^x

A person invests 1 lakh rupees in shares and the amount is twice at the end of each year. So, total amount (in lakhs) after x years is

f(x)=1(2)^x

f(x)=(2)^x

7 0
4 years ago
Which number is a common factor of 27 and 45?<br> A) 5 <br> B) 9 <br> C) 12 <br> D) 15
mestny [16]

Answer:

We found the factors and prime factorization of 27 and 45. The biggest common factor number is the GCF number. So the greatest common factor 27 and 45 is 9.

Step-by-step explanation:

6 0
3 years ago
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Scrat [10]

Answer:

A=B+n

Step-by-step explanation:

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4 0
3 years ago
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Find the volume of the solid generated by revolving the region bounded by
Rama09 [41]

Answer:

V =\dfrac{25\pi}{\sqrt{2}}

Step-by-step explanation:

given,

y=5√sinx

Volume of the solid by revolving

V = \int_a^b(\pi y^2)dx

a and b are the limits of the integrals

now,

V = \int_a^b(\pi (5\sqrt{sinx})^2)dx

V =25\pi \int_{\pi/4}^{\pi/2}sinxdx

\int sin x = - cos x

V =25\pi [-cos x]_{\pi/4}^{\pi/2}

V =25\pi [-cos (\pi/2)+cos(\pi/4)]

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volume of the solid generated is equal to V =\dfrac{25\pi}{\sqrt{2}}

4 0
4 years ago
1.Encuentra de dos formas diferentes el área de las figuras mostradas en cada literal:​
MA_775_DIABLO [31]

Answer:

Cuadrilátero A: A = y^{2}+4\cdot y +4

Cuadrilátero B: A = a^{2}+6\cdot a + 9

Step-by-step explanation:

Existen dos formas distintas de determinar las áreas de cada cuadrilátero:

(i) <em>Obtener el área de cada cuadrado y sumar los resultados.</em>

(ii) <em>Calcular los lados del cuadrilátero grande y determinar el área. </em>

Cuadrilátero A

Método (i)

A = y^{2}+2\cdot y +4+2\cdot y

A = y^{2}+4\cdot y +4

Método (ii)

A = (y+2)\cdot (y+2)

A = y^{2}+4\cdot y + 4

Cuadrilátero B

Método (i)

A = a^{2}+3\cdot a +9 + 3\cdot a

A = a^{2}+6\cdot a +9

Método (ii)

A = (a+3)\cdot (a+3)

A = a^{2}+6\cdot a + 9

8 0
3 years ago
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