First of all we need to find a representation of C, so this is shown in the figure below.
So the integral we need to compute is this:

So, as shown in the figure, C = C1 + C2, so:
Computing first integral:
Applying derivative:

Substituting this value into

Computing second integral:
Applying derivative:

Substituting this differential into


We need to know the limits of our integral, so given that the variable we are using in this integral is x, then the limits are the x coordinates of the extreme points of the straight line C2, so:
![I_{2}= -8\int_{4}^{8}}dx=-8[x]\right|_4 ^{8}=-8(8-4) \rightarrow \boxed{I_{2}=-32}](https://tex.z-dn.net/?f=I_%7B2%7D%3D%20-8%5Cint_%7B4%7D%5E%7B8%7D%7Ddx%3D-8%5Bx%5D%5Cright%7C_4%20%5E%7B8%7D%3D-8%288-4%29%20%5Crightarrow%20%5Cboxed%7BI_%7B2%7D%3D-32%7D)
Finally:
H(x)=-16t^2+300
The average rate is the change in h divided by the change in t, mathematically:
r=(h(3)-h(0))/(t2-t1), in this case:
r=(-16*9+300-0-300)/(3-0)
r=-144/3
r= -48 ft/s
since 17 is a prime number and 26 is not a multiple of 17
17/26 is in simplest form
Hello!
To find the surface area of a cylinder you use the equation

SA is surface area
r is radius
h is height
PUt in the values you know

Square the number

Multiply 7 and 18

Multiply 126 by 2

Multiply the 49 by 2

Add

The answer is

Hope this helps!
Lisa took a trip to Kuwait upon leaving she decided to convert all of her dinars back into dollars how many