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PilotLPTM [1.2K]
3 years ago
10

Ms. Walch works as a car salesperson. She earns a monthly base salary of $ 4,000 Plus $ 500 commission for each car she sells. H

ow many cars does Ms. Walsh need to sell in a given month to earn a total salary of $ 10,000 for that month?
Mathematics
2 answers:
Kazeer [188]3 years ago
8 0

Answer:

20 cars

Step-by-step explanation:

10,000 ÷ 500 = 20

yan [13]3 years ago
4 0

Answer:

2 cars

Step-by-step explanation:

4,000 + 500 = 4,500 x 2 =10,000

thus its 2 cars

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BartSMP [9]

Let AB = t. And since X lies in the middle, so AX=BX = t/2 .

Let the height of the smaller flagpole is AO and of larger flagpole is BP .

Using tangent ratio rule in each triangle, we will get

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Answer:

0.28 is a decimal and 28/100 or 28% is the percentage for 7/25.

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3 years ago
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Use integration by parts to derive the following formula from the table of integrals.
emmasim [6.3K]

Answer:

I= (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C (for a≠0)

Step-by-step explanation:

for

I= ∫x^n . e^ax dx

then using integration by parts we can define u and dv such that

I= ∫(x^n) . (e^ax dx) = ∫u . dv

where

u= x^n → du = n*x^(n-1) dx

dv= e^ax  dx→ v = ∫e^ax dx = (e^ax) /a ( for a≠0 .when a=0 , v=∫1 dx= x)

then we know that

I= ∫u . dv = u*v - ∫v . du + C

( since d(u*v) = u*dv + v*du → u*dv = d(u*v) - v*du → ∫u*dv = ∫(d(u*v) - v*du) =

(u*v) - ∫v*du + C )

therefore

I= ∫u . dv = u*v - ∫v . du + C = (x^n)*(e^ax) /a - ∫ (e^ax) /a * n*x^(n-1) dx +C = = (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C

I= (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C (for a≠0)

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3 years ago
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EleoNora [17]

Answer:

Step-by-step explanation:

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2 years ago
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