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PilotLPTM [1.2K]
3 years ago
10

Ms. Walch works as a car salesperson. She earns a monthly base salary of $ 4,000 Plus $ 500 commission for each car she sells. H

ow many cars does Ms. Walsh need to sell in a given month to earn a total salary of $ 10,000 for that month?
Mathematics
2 answers:
Kazeer [188]3 years ago
8 0

Answer:

20 cars

Step-by-step explanation:

10,000 ÷ 500 = 20

yan [13]3 years ago
4 0

Answer:

2 cars

Step-by-step explanation:

4,000 + 500 = 4,500 x 2 =10,000

thus its 2 cars

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$1 = 2 weeks

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<u>Multiply by 800:</u>

$1 x 800 = 2 x 800 weeks

$800 = 1600 weeks

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Answer: You need <u>1600 weeks </u>to get $800

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Which value of n makes this equation true?
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Below, explain why we are allowed the
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https://tinyurl.com/smwjw6yn

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NASA is conducting an experiment to find out the fraction of people who black out at G forces greater than 6 6 . In an earlier s
Xelga [282]

Answer:

The sample size must be atleast 502 to have a margin of error of 0.03

Step-by-step explanation:

We are given the following in the question:

Proportion = 0.32

\hat{p} = 0.32

Level of significance = 0.15

Margin of error = 0.03

Formula for margin of error =

z_{stat}\times \sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

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We have to find the sample size such that the margin of error is atmost 0.03.

Putting values, we get,

z_{stat}\times \sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\leq 0.03\\\\1.44\times \sqrt{\dfrac{0.32(1-0.32)}{n}}\leq 0.03\\\\\sqrt{n}\geq 1.44\times \dfrac{\sqrt{0.32(1-0.32)}}{0.03}\\\\\sqrt{n}\geq 22.39\\n\geq 501.3121\\\Rightarrow n\geq 502

Thus, the sample size must be atleast 502 to have a margin of error of 0.03 in approximation of proportion of people who would black out at 6 or more Gs.

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3 years ago
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