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2 years ago

the mean of 10 students is 16 . When a student is added, the mean becomes 18. Find the age of the student added

Mathematics

1 answer:

MakcuM [25]2 years ago

5 0

Answer:

Step-by-step explanation:

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a hardware stores mixes paint in a ratio of three parts blue to five parts yellow to make two gallons of lime green. A ration of

Rufina [12.5K]

7B+5Y=487B+1Y=40Subtracting Eqn 2 from 1 we get 4Y=8so Y = $2 and X=$38/7

4 0

2 years ago

What is the answer to 8(3.5x−2)≥40

sammy [17]

Answer:

Step-by-step explanation:

Distribute 8:

8 (3.5x - 2) ≥ 40

28x - 16 ≥ 40

Add 16:

28x ≥ 40 + 16

28x ≥ 56

Divide by 28:

x ≥ 56 ÷ 28

x ≥ 2

8 0

2 years ago

Read 2 more answers

There are 17 kites in a kite-flying contest at the beach. There are 3 times as many box kites as butterfly kites. There are 2 mo

alina1380 [7]

C is your answer. 5x + 2 = 17

First let’s get them all in terms of x:
Box kites = 3x
Dragon kites = x + 2
Butterfly kites = x

Adding all those up:

x + 3x + x + 2 = 17
Combine like terms:
5x + 2 = 17

6 0

3 years ago

Read 2 more answers

HELP ME PLEASE, I'D LIKE TO UNDERSTAND HOW TO DO THIS TOO SO I'LL GIVE BRAINLY FOR THE RIGHT ANSWER WITH GOOD AND UNDERSTANDING

umka2103 [35]

Answer:

34 goes in the blank.

Step-by-step explanation:

Triangle ABC is congruent to triangle TUV implies the following:

Angle A is congruent to angle T.

Angle B is congruent to angle U.

Angle C is congruent to angle V.

Side AB is congruent to side TU.

Side BC is congruent to side UV.

Side CA is congruent to side VT.

Note: Order tells you everything in a congruence statement.

Since side BC is congruent to UV, then the measure of side BC is equal to the measure of side UV.

8x+2=7x+6

Subtract 7x on both sides:

1x+2=6

x+2=6

Subtract 2 on both sides:

x=6-2

x=4

So if x=4, then the measure of side BC is 8x+2=8(4)+2=32+2=34.

So the measure of BC is 34 cm.

5 0

3 years ago

Need answer to 4 and 5

algol13

Answer:

Substitute n =1, 2, 3, 4, 5 to get the first five terms.

Step-by-step explanation:

(4). $g_n = 2 . 3^{n - 1}$

To find the first term, substitute n = 1.

Therefore, $g_1 = 2 . 3^{1 - 1} = 2 . 3^{0} = 2 . 1$ = 2

$g_2 = 2 . 3^{2 - 1} = 2 . 3$ = 6

$g_3 = 2 . 3^{3 - 1} = 2 . 3^{2} = 2 . 9$ = 18

$g_4 = 2 . 3^{4 - 1} = 2 . 3^{3} = 2 . 27$ = 54

$g_5 = 2 . 3^{5 - 1} = 2 . 3^{4} = 2 . 81$ = 168

Therefore the first five terms of the sequence are: 2, 6, 18, 54, 168.

(5). $t_n = \frac{2}{3}t_{n - 1}$

$t_2 = \frac{2}{3} t_{2 - 1} = \frac{2}{3}t_1 = \frac{2}{3}6$ = 4

$t_3 = \frac{2}{3} t_2 = \frac{2}{3}. 4 = \frac{8}{3}$

$t_4 = \frac{2}{3}t_3 = \frac{2}{3}\frac{8}{3} = \frac{16}{9}$

$t_5 = \frac{2}{3}t_4 = \frac{2}{3}\frac{16}{9} = \frac{32}{27}$

Therefore the first five terms in the sequence are: 6, 4, 8/3, 16/9, 32/27.

8 0

3 years ago

the mean of 10 students is 16 . When a student is added, the mean becomes 18. Find the age of the student added​

the mean of 10 students is 16 . When a student is added, the mean becomes 18. Find the age of the student added