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3 years ago

Is AFGH ~ AJKL? If so, identify the similarity postulate or theorem that

Mathematics

1 answer:

ad-work [718]3 years ago

5 0

Answer: B. Cannot be determined

Explanation:

We can't use SAS since we don't have two pairs of proportional sides. We only know one pair of sides. This also rules out SSS as well since we'd need 3 pairs of proportional sides.

We can't use AA because we don't have two pairs of congruent angles.

Currently, we simply don't have enough information to determine if the triangles are similar or not.

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Mr. Erickson will be living in the forest

aliina [53]

$\huge{\boxed{60\ \text{ft}^{3}}}$

We will assume the tent is in the shape of a triangular prism.

The volume of a triangular prism can be found with the following formula, where $b$ is the width at the base, $h$ is the height, and $l$ is the length.

$V=\frac{1}{2}bhl$

Substitute in the known values.

$V=\frac{1}{2}*5*3*8$

Simplify — use multiplication.

$V=\frac{5}{2}*3*8$

$V=\frac{15}{2}*8$

$V=\frac{120}{2}$

Simplify — use division.

$V=\large{\boxed{60\ \text{ft}^{3}}}$

The volume — or in this case, the amount of living space — is $60\ \text{cubic feet}$ .

7 0

3 years ago

The volume of a 10 ounce box of cheerios is 258.75in3. the length of the box is 4 inches less than the height and the width is 3

Marina86 [1]

Answer:

Height of the box = 11.5 in

Step-by-step explanation:

Let h be the height of the box.

Assuming the volume of the Box is $258.75\ in^3$ .

Given:

Length = Height - 4 = h - 4

Width = 3 in

We need to find the height of the box.

Solution:

We know that the volume of the box.

$Volume = Length\times height\times width$

Substitute all given value in above formula.

$258.75 = (h-4)\times h\times 3$

Rewrite the equation as:

$258.75 = 3h(h-4)$

$258.75 = 3h^2-12h$

$3h^2-12h-258.75=0$

whole equation divided by 3.

$h^2-4h-86.25=0$

Use quadratic formula with $a = 1, b = -4,c=-86.25$

$h=\frac{-b\pm \sqrt{(b)^{2}-4ac}}{2a}$

Put these a, b and c value in above equation.

$h=\frac{-(-4)\pm \sqrt{(-4)^{2}-4(1)(-86.25)}}{2(1)}$

$h=\frac{4\pm \sqrt{16+345}}{2}$

$h=\frac{4\pm \sqrt{361}}{2}$

$h=\frac{4\pm 19}{2}$

For positive sign

$h=\frac{23}{2}$

h = 11.5 in

For negative sign

$h=\frac{-15}{2}$

h = -7.5

We take positive value of h.

Therefore, the height of the box h = 11.5 in

4 0

2 years ago

Why is it important to check all solutions to radical equations?

aleksklad [387]

Hello.

The solutions found to radical equations are not necessarily viable. They sometimes result in inequalities, and have to be checked.

Hope I helped.

4 0

3 years ago

Read 2 more answers

Write as a logarithmic equation. 1004 = 100,000,000

horrorfan [7]

Answer:

well it would b 36,87 =x-87

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

2 planes fly in opposite directions. One travels 475 mi/h and the other 525 mi/h . How long will it take before they are 6,000 m