Answer:
No not correct
Step-by-step explanation:
We are given information that Maya came to know that 0.63 pf Pal school is female and 0.47 of Elm school is female.
Without knowing the total number of students in each school, we cannot conclude that 0.63 is greater than 0.47
For example, say number of students in Oak school be 100, and in Elm school be 200
Females in Oak school = 0.63(100) =63
Females in Elm school = 0.47(200) = 94
We find that there are more females in Elm school
So with the information given, we cannot conclude she is correct , there are chances for her being wrong also.
Answer:
please pay attention during your classes.
Step-by-step explanation:
11.9 would be the correct answer I believe
Answer:
(115.2642, 222.7358).
Step-by-step explanation:
Given data:
type A: n_1=60, xbar_1=1827, s_1=168
type B: n_2=180, xbar_2=1658, s_2=225
n_1 = sample size 1, n_2= sample size 2
xbar_1, xbar_2 are mean life of sample 1 and 2 respectively. Similarly, s_1 and s_2 are standard deviation of 1,2.
a=0.05, |Z(0.025)|=1.96 (from the standard normal table)
So 95% CI is
(xbar_1 -xbar_2) ± Z×√[s1^2/n1 + s2^2/n2]
=(1827-1658) ± 1.96×sqrt(168^2/60 + 225^2/180)
= (115.2642, 222.7358).
Answer:
P(t)=30
Step-by-step explanation:
Plug in t=6 into the equation: P(t)=t^2-t
So P(t)= (6)^2-6
P(t)=36-6
P(t)=30