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2 years ago

Over what interval is the function in this graph constant

Mathematics

1 answer:

kolezko [41]2 years ago

6 0

The interval for which the graph remains constant is; Option C: -4 ≤ x ≤ -2

<h3>How to find graph intervals?</h3>

The interval on the graph at which it is constant would be the x-interval where the value of y remains the same.

Now, from the given graph, we can see that from x = -2 to x = -4, the value of y remains the same at y = -3.

Thus, we can conclude that the interval for which the graph remains constant is; -4 ≤ x ≤ -2

Read more about graph intervals at; brainly.com/question/453733

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When graphed on a coordinate plane Beth’s house is located at (4, 3) and the coffee shop is located at the point (–2, –1).

MissTica

Answer:

2/3 miles

Step-by-step explanation:

this question is basically asking you to find the slope between two points: (4,3) and (-2, -1)

how to find slope: (y1 - y2)/ (x1-x2)

so:

y1 =3, y2= -1

x1 = 4, x2 = -2

[3- (-1)]/[4-(-2)]

[3+1]/[4+2]

4/6

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Now we ask ourselves, "how many times does 12 go into 50 without going over?"

12 × 4 = 48

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4 years ago

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3 years ago

Graph the function with the given domain then identify the range of the function

alexira [117]

When the domain is ≥ to 0, that basically means that x must be ≥ 0.
Imagine what that looks like.
It would just be the right side of the coordinate plane, right? Because the left side would have negative x values.

We're basically just going to be graphing the line $y=3x-2$ , except only the part on the right side of the coordinate plane because of course x ≥ 0.

When you have an equation in the form of $y=mx+b$ , $b$ is going to be the y-intercept (the point where the line intersects the y-axis) and $m$ is going to be the slope.

Since the y-intercept is -2, draw a point at (0, -2).

Then, use the slope to find another point on the line.
The slope is 3, which as a fraction would be $\frac{3}1$ .
Slope = rise over run, so basically every change of 1 in x = a change of 3 in y.
Draw a point 3 up and 1 over from (0, -2).<em> (at (1, 1))

</em>Then draw a line through the two points we have graphed. Don't draw past the y-axis on the left side, because of course x ≥ 0.
<em>
And there you go!
</em>
The range of the function is basically the possible values y can have.
Well, since it's not going any lower than the y-intercept (0, -2), the range is ≥ -2.<em>

</em>

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3 years ago