Answer:
equation of the line is y=x+1
Step-by-step explanation:
the equation of a line has the form y = mx + b
while m is for the slope and b is for the y-intercept.
you can see from the graph that the line intercepts the y-axis at y=1 this is the b.
you can get the slope of the graph by taking two points from the graph lets say (1, 2) and (3, 4) then using this formula:
<h2>

</h2>
in our case it will be:

then just substitute the values for m and b.
Answer:
A and B are correct, but A is most correct.
Step-by-step explanation:
just do Pythagorean theorem and see which numbers add up to each other. if you do them for all 4 answers, you see d and c do not equal to each other. b is almost correct, and a comes out exact.
Answer: 12
Step-by-step explanation:
6c + 11= 2c + 59
Collect like terms
6c - 2c = 59 - 11
4c = 48
c = 48/4
c = 12
Using the normal distribution, it is found that there was a 0.9579 = 95.79% probability of a month having a PCE between $575 and $790.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:
.
The probability of a month having a PCE between $575 and $790 is the <u>p-value of Z when X = 790 subtracted by the p-value of Z when X = 575</u>, hence:
X = 790:


Z = 1.8
Z = 1.8 has a p-value of 0.9641.
X = 575:


Z = -2.5
Z = -2.5 has a p-value of 0.0062.
0.9641 - 0.0062 = 0.9579.
0.9579 = 95.79% probability of a month having a PCE between $575 and $790.
More can be learned about the normal distribution at brainly.com/question/4079902
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Answer: $0.65
Step-by-step explanation:
Amount for the magazine in a regular newsstand for one year:
1.95*12=$23.4
Amount saved per issue with subscription:
(23.4-15.60) ÷ 12 = $0.65 per issue is saved with a subscription