Question

Will wanted to solve the problem

Answer 1

The large division mathematical problem can be solved using partial

quotient;

The methods that could be used to find the quotient are;

B. Subtract (30 × 12) from 468to get 108. Subtract (9 × 12) from 108 to have

0 remainder.

C. Subtract (20 × 12) from 468 to get 228. Subtract (10 × 12) from 228 to get

108. Subtract (3 × 12) from 108 to get 72. Subtract 6 × 12 from 72 to get a 0

remainder.

Reason:

The division of 468 by 12 using partial quotient gives;

12|$\overline{468}$

  ${}$ -360  ← 30 × 12

${}$      108

  ${}$   -108  ← 9 × 12

${}$           0

Therefore, the quotient = 30 + 9 = 39

Therefore, option B. can be used to find the quotient;

Option B: Subtract (30 × 12) from 468; 468 - 30 to get 108. Subtract (9 ×

12) from 108 to have 0 remainder.

The method in option C which is expressed as follows;

468 - 20 × 12 = 228

228 - 10 × 12 = 108

108 - 3 × 12 = 72

72 - 6 × 12 = 0

Therefore, option is C. could be used and the statement is expressed as follows;

Subtract (20 × 12) from 468 to get 228. 468 - (20 × 12) = 228

Subtract (10 × 12) from 228 to get 108. 228 - (10 × 12) = 128

Subtract (3 × 12) from 108 to get 72. 108 - (3 × 12) = 72

Subtract (6 × 12) from 72 to get a 0 remainder.

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