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The largest consecutive integers whose sum is less than 46 are x= 21 and x+1=22
Step-by-step explanation:
Let the integers be:
x and x+1
The sum of these integers is less than 46
Solving and finding value of x:
So, the integers will be less than 22.5
The largest numbers are: 21 and 22
So, the largest consecutive integers whose sum is less than 46 are x= 21 and x+1=22
Keywords: Finding integers
Learn more about finding integers at:
#learnwithBrainly
Answer:
a) 2
b) 5
c) -1
d) x
Step-by-step explanation:
We know the properties of log function as:
1) log(AB) = log(A) + log(B)
2)
3) log(aᵇ) = b × log(a)
also,
4)
Given:
a. y = log₂(2²)
thus, using 3
y = 2log₂(2)
or using 4
y = 2 ×
or
y = 2 × 1 = 2
b. y = log₂(2⁵)
thus, using 3
y = 5 × log₂(2)
or using 4
y = 5 ×
or
y = 5 × 1 = 5
c. y = log₂(2⁻¹)
thus, using 3
y = -1 × log₂(2)
or using 4
y = -1 ×
or
y = -1 × 1 = -1
d. y = log₂(2ˣ)
thus, using 3
y = x × log₂(2)
or using 4
y = x ×
or
y = x × 1 = x