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Dimas [21]
2 years ago
6

What is the ratio of the area of the inner square to the area of the outer square?

Mathematics
1 answer:
Setler [38]2 years ago
7 0

Answer:

Step-by-step explanation:

If we are looking for the ratio of the area of the inner square to the area of the outer square, that means that we need the areas of each of these squares, and we need to find the areas without any numbers. But that's ok; the answer they want is not a number answer. The answer will have a's and b's in it instead of numbers.

First the area of the inner square. Here we go:

Look at the triangle in the lower left corner of this coordinate plane. It is a right triangle. The height of it is b. That's because the height is a "y" thing and the y-coordinates of each of those sets of coordinates is b and 0. The height is then b - 0 = b.

The length of the base is a - b. That's because the length is an "x" thing and the x-coordinates of each of those sets of coordinates is (a - b) and 0. The length is then a - b - 0 = a - b.

Now we need the length of the hypotenuse which also serves as one of the sides of the inner square. Using Pythagorean's Theorem, we can find the length of the hypotenuse, which I will label as "?":

?^2=b^2+(a-b)^2 and

?^2=b^2+a^2-2ab+b^2 and

?^2=a^2-2ab+2b^2 so

?, the length of the hypotenuse, is

?=\sqrt{a^2-2ab+2b^2} and now we can use that to find the area of the inner square. The formula for a square's area is

A=s^2 so

A=(\sqrt{a^_2}-2ab+2b^2})^2 which gives us finally:

A=a^2-2ab+2b^2 **

Now for the outer square. Those blue triangles you see are all congruent. We can use the side lengths for the triangles we found above to find the length of a side of the outer square. One side of the outer square is made up of one base length of these triangles and one height. We found the base length to be (a - b) and the height to be b; therefore, the length of one side of the outer square is b + (a - b) which is just "a". That's is, just a length of "a". The area is found by multiplying this side length by itself, so the area of the outer square is

A = a²

The ratio of the area of the inner to the outer is:

\frac{A_i}{A_o}:\frac{a^2-2ab+2b^2}{a^2} and that does not reduce.

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3. A computer is worth $4000 when it is new. After each year it is worth half what it was the previous year
MrMuchimi

Answer:

Answer is 500

btw did round sorry

Step-by-step explanation:

First year

4,000 divided by 2,000=2,000

Second year

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What is 6 tenths 20 hundredths 4 ones and 50 hundreds
Elina [12.6K]

Answer:

The answer is 25064.

Step-by-step explanation:

<u>There is a mistake in the question so the correct is below:</u>

What is 6 tenths 20 thousandths 4 ones and 50 hundreds.

Now, to solve it:

So, we arrange it in sequence:

20 thousandths 50 hundreds 6 tenths and 4 ones.

Now,

20 thousandths = 20 <u>000</u>

50 hundreds      = 50 <u>00</u>

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3 0
3 years ago
Lesson 6.07
Oduvanchick [21]

Answer:

A) Interval estimate for those that want to get out earlier = (35%) ± (4%) = (31%, 39%)

Interval estimate for those that want to get out later = (39%) ± (4%) = (35%, 43%)

B) The group that wants to get out of school earlier can win after all the votes are counted if their true population proportion takes on a value that is higher than the closest true population proportion (for the group that wants to get out of school later)

That is, in the (31%, 39%) and (35%, 43%) obtained in (a), a range of (35.1%, 39%) and (35%, 38.9%) show how possible that the group that wants to get out of school earlier can win after all the votes are counted.

Step-by-step explanation:

The Interval estimate for the a proportion is basically an interval of range of values where the true population proportion can be found with a certain level of confidence.

Mathematically,

Interval estimate = (Sample proportion) ± (Margin of error)

Margin of Error is the width of the confidence interval about the proportion.

a) Find the interval estimates

i) for those that want to get out earlier and

ii) those that want to get out later.

i) Sample proportion of those that want to get out earlier = 35%

Margin of Error = 4%

Interval estimate for those that want to get out earlier = (35%) ± (4%) = (31%, 39%)

ii) Sample proportion of those that want to get out later = 39%

Margin of Error = 4%

Interval estimate for those that want to get out later = (39%) ± (4%) = (35%, 43%)

b) Explain how it would be possible for the group that wants to get out of school earlier to win after all the votes are counted.

Since the interval estimates represent the range of values that the true population proportion can take on for each group that prefer a particular option, the group that wants to get out of school earlier van have their proportion take on values between 31% and 39%. If their true population takes on a value that is highest (which is very possible from the interval estimate), and the group with the highest proportion in the sample, (the group that wants to get out of school later, whose true population proportion can take between 35% and 43%) has a true population proportion that is less than that of the group that wants to get out of school earlier, then, the group that wants to get out of school earlier can win after all the votes are counted.

Hope this Helps!!!

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Step-by-step explanation:

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