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2 years ago

What is x abc def A. 45 B. 60 C. 75 D. 30

Mathematics

2 answers:

BigorU [14]2 years ago

5 0

Answer:

Step-by-step explanation:

tankabanditka [31]2 years ago

5 0

C. 75

60 + 45 = 105
180-105= 75

therefore 75 is your answer

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Given the following exponential function identify whether the change represents growth or decay and determine the percentage rat

kotegsom [21]

Y=g474xibe it’s that because had more answer to the q

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2 years ago

David says he has 2/3 of a pipe length left, while Don says he has 11/16 of a length left. Which person has the longest section

Kruka [31]

Answer:

Don

Step-by-step explanation:

1. We make the fractions have common denominators so it is easier to compare them. We can do this buy multiplying 2/3 by a factor of 16, so it becomes 32/48. For 11/16, we multiply by a factor of 3 so it becomes 33/48. It is now apparent that Don has the longer pipe.

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2 years ago

Write the edge of the cube in terms of its volume

Elanso [62]

Answer:

Step-by-step explanation:

The formula for the volume is given by

(side)3=volume

Since we have the volume, we must take the cube root of the volume to find the length of any one side (since it is a cube, all of the sides are equal).

(side)3−−−−−−√3=side=volume−−−−−−√3

Plugging in 216 for the volume, we end up with

side=6 cm

3 0

1 year ago

Read 2 more answers

Match the parabolas represented by the equations with their vertices. y = x2 + 6x + 8 y = 2x2 + 16x + 28 y = -x2 + 5x + 14 y = -

GaryK [48]

Consider all parabolas:

$y = x^2 + 6x + 8,\\y=x^2+6x+9-9+8,\\y=(x^2+6x+9)-1,\\y=(x+3)^2-1.$

When x=-3, y=-1, then the point (-3,-1) is vertex of this first parabola.

$y = 2x^2 + 16x + 28=2(x^2+8x+14),\\y=2(x^2+8x+16-16+14),\\y=2((x^2+8x+16)-16+14),\\y=2((x+4)^2-2)=2(x+4)^2-4.$

When x=-4, y=-4, then the point (-4,-4) is vertex of this second parabola.

$y =-x^2 + 5x + 14=-(x^2-5x-14),\\y=-(x^2-5x+\dfrac{25}{4}-\dfrac{25}{4}-14),\\y=-((x^2-5x+\dfrac{25}{4})-\dfrac{25}{4}-14),\\y=-((x-\dfrac{5}{2})^2-\dfrac{81}{4})=-(x-\dfrac{5}{2})^2+\dfrac{81}{4}.$

When x=2.5, y=20.25, then the point (2.5,20.25) is vertex of this third parabola.

$y =-x^2 + 7x + 7=-(x^2-7x-7),\\y=-(x^2-7x+\dfrac{49}{4}-\dfrac{49}{4}-7),\\y=-((x^2-7x+\dfrac{49}{4})-\dfrac{49}{4}-7),\\y=-((x-\dfrac{7}{2})^2-\dfrac{77}{4})=-(x-\dfrac{7}{2})^2+\dfrac{77}{4}.$

When x=3.5, y=19.25, then the point (3.5,19.25) is vertex of this fourth parabola.

$y =2x^2 + 7x +5=2(x^2+\dfrac{7}{2}x+\dfrac{5}{2}),\\y=2(x^2+\dfrac{7}{2}x+\dfrac{49}{16}-\dfrac{49}{16}+\dfrac{5}{2}),\\y=2((x^2+\dfrac{7}{2}x+\dfrac{49}{16})-\dfrac{49}{16}+\dfrac{5}{2}),\\y=2((x+\dfrac{7}{4})^2-\dfrac{9}{16})=2(x+\dfrac{7}{4})^2-\dfrac{9}{8}.$

When x=-1.75, y=-1.125, then the point (-1.75,-1.125) is vertex of this fifth parabola.

$y =-2x^2 + 8x +5=-2(x^2-4x-\dfrac{5}{2}),\\y=-2(x^2-4x+4-4-\dfrac{5}{2}),\\y=-2((x^2-4x+4)-4-\dfrac{5}{2}),\\y=-2((x-2)^2-\dfrac{13}{2})=-2(x-2)^2+13.$

When x=2, y=13, then the point (2,13) is vertex of this sixth parabola.

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2 years ago

Wren recorded an outside temperature of -2 Fahrenheit at 8 a.m. When she checked the temperature again, it was 4 Fahrenheit at 1

castortr0y [4]

Rise over run. as time increases the temperature rises. starting at 8am and -2°f.
At 12pm the temperature rose to 4°f.
that's a difference of 4 hours and 6 degrees. for every hour, it rose 1.5 degrees. the slope is 1.5/1

7 0

2 years ago