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s344n2d4d5 [400]
3 years ago
9

Use picture and numbers to show how to add 3+1 in any order

Mathematics
1 answer:
coldgirl [10]3 years ago
3 0
1+3
3+1
you can draw out apples and pears for example
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Confidence Interval Mistakes and Misunderstandings—Suppose that 500 randomly selected recent graduates of a university were as
kvv77 [185]

Answer:

The correct 95% confidence interval is (8.4, 8.8).

Step-by-step explanation:

The information provided is:

n=500\\\bar x=8.6\\\sigma=2.2

(a)

The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

CI=\bar x\pm z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The 95% confidence interval for the average satisfaction score is computed as:

8.6 ± 1.96 (2.2)

This confidence interval is incorrect.

Because the critical value is multiplied directly by the standard deviation.

The correct interval is:

8.6\pm 1.96 (\frac{2.2}{\sqrt{500}})=8.6\pm 0.20=(8.4,\ 8.6)

(b)

The (1 - <em>α</em>)% confidence interval for the parameter implies that there is (1 - <em>α</em>)% confidence or certainty that the true parameter value is contained in the interval.

The 95% confidence interval for the mean rating, (8.4, 8.8) implies that the true there is a 95% confidence that the true parameter value is contained in this interval.

The mistake is that the student concluded that the sample mean is contained in between the interval. This is incorrect because the population is predicted to be contained in the interval.

(c)

The (1 - <em>α</em>)% confidence interval for population parameter implies that there is a (1 - <em>α</em>) probability that the true value of the parameter is included in the interval.

The 95% confidence interval for the mean rating, (8.4, 8.8) implies that the true mean satisfaction score is contained between 8.4 and 8.8 with probability 0.95 or 95%.

Thus, the students is not making any misinterpretation.

(d)

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

In this case the sample size is,

<em>n </em>= 500 > 30

Thus, a Normal distribution can be applied to approximate the distribution of the alumni ratings.

7 0
3 years ago
What does 7/18 + 2/27=
victus00 [196]

The answer would be 25/54

4 0
3 years ago
Read 2 more answers
In one day, a book store earned $253 in sales for 4 copies of a new cookbook and 5 copies of a new science fiction novel. On the
Aloiza [94]

Answer: cookbook $40 and science $15

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
The price of an item yesterday was 130. Today, the price fell to 91 . Find the percentage decrease.
Shalnov [3]

Answer:

30%

Step-by-step explanation:

130-91=39

39 / 130 =0.3

0.3x100=30

and you got the answer!

7 0
2 years ago
Read 2 more answers
Solve this system of linear equations. Separate the x- and y-values with a comma.
vodomira [7]

Answer:

x = \frac{5}{2}, y = \frac{5}{4}

Step-by-step explanation:

1. Isolate for x in one of the equations:

2x = 9x - 14y

2x-9x = 9x-9x -14y

-7x = -14y

-7x/-7 = -14y/-7

x = 2y

2. Substitute 2y in for x in the second equation:

9(2y) = 40 - 14y

3. Simplify:

18y = 40 - 14y

4. Isolate for y:

18y+14y = 40 -14y+14y

32y = 40

32y/32 = 40/32

y = \frac{5}{4}

5. Substitute the new y-value into the simplified expression x = 2y:

x = 2(5/4)

x = \frac{5}{2}

hope this helps!

7 0
2 years ago
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