Answer:
None of these.
Step-by-step explanation:
Let's assume we are trying to figure out if (x-6) is a factor. We got the quotient (x^2+6) and the remainder 13 according to the problem. So we know (x-6) is not a factor because the remainder wasn't zero.
Let's assume we are trying to figure out if (x^2+6) is a factor. The quotient is (x-6) and the remainder is 13 according to the problem. So we know (x^2+6) is not a factor because the remainder wasn't zero.
In order for 13 to be a factor of P, all the terms of P must be divisible by 13. That just means you can reduce it to a form that is not a fraction.
If we look at the first term x^3 and we divide it by 13 we get 
we cannot reduce it so it is not a fraction so 13 is not a factor of P
None of these is the right option.
Answer:
$67
Step-by-step explanation:
So 5x12+7=C
PEDMAS so:
5x12 = 60
60+7 = 67
67 = C
The area of a 2D form is the amount of space within its perimeter. The area of the arrow is 11.25 in².
<h3>What is an area?</h3>
The area of a 2D form is the amount of space within its perimeter. It is measured in square units such as cm2, m2, and so on. To find the area of a square formula or another quadrilateral, multiply its length by its width.
For the given problem, the image is given below.
The area of the arrow is,
Area = Area of rectangle + Area of triangle
= (1.5 in × 4.5 in) + (0.5×3×3)
= 6.75 in² + 4.5 in²
= 11.25 in²
Hence, the area of the arrow is 11.25 in².
Learn more about the Area:
brainly.com/question/1631786
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Answer:
(a, b) = (0, -15)
Step-by-step explanation:
In "cis" form the product of two complex numbers is the product of their magnitudes at the angle that is the sum of their angles. I find this the easiest way to multiply complex numbers.
z1 × z2 = (3 cis π)(5 cis π/2)
= (3·5) cis (π +π/2)
= 15 cis 3π/2
Of course, "cis" is short for "cosine + i·sine", so you have ...
z1 × z2 = 15 cis 3π/2 = 15(cos(3π/2) +i·sin(3π/2))
= 15(0 +i·(-1))
= 0 -15i
(a, b) = (0, -15)
The answer is: 10 x¹³ y¹⁰ .
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1x^8 * 2y^(10) * 5x^5 =
1* 2* 5 * x^8 * x^5 * y^(10) =
10 * x^(8+5) * y^(10) =
10 * x^(13) * y^(10) = 10 x^(13) y^10 ; write as:
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10 x¹³ y¹<span>⁰ .
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