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Over [174]
3 years ago
10

keith is the leading goal scorer for a team in an hockey league. last season he scored 42 goals in 82 games. assuming he scores

goals at a constant rate what is the slope of line that represents this relationship if the number of games is along the x-axis and the number of goals is along the y-axis
Mathematics
1 answer:
MAXImum [283]3 years ago
4 0

Answer:

0.512 goals per game

Step-by-step explanation:

Given:

The number of games is represented by 'x' and number of goals is represented by 'y'.

Now, 'y' varies directly with x and at a constant rate.

A direct relationship line is given as:

y=mx

Where, 'm' is the constant rate of change.

Now, for x=82,y=42

So, a point on the line is given as (82, 42).

Plug in the given values in the above equation and solve for 'm'. This gives,

42=82m\\m=\frac{42}{82}\\m=0.512

Therefore, Keith scores at a constant rate of 0.512 goals per game.

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\large\begin{array}{l} \left\{\!\begin{array}{l} \mathsf{f(x)=x^2-6x+2}\\ \mathsf{g(x)=\sqrt{x}}\\ \end{array}\right. \end{array}


\large\begin{array}{l} \textsf{a) }\mathsf{(f\circ g)(x)}\\\\ =\mathsf{f\big[g(x)\big]}\\\\ =\mathsf{\big[g(x)\big]^2-6\cdot g(x)+2}\\\\ =\mathsf{\big[\sqrt{x}\big]^2-6\sqrt{x}+2}\\\\\\ \therefore~~\boxed{\begin{array}{c}\mathsf{(f\circ g)(x)=x-6\sqrt{x}+2} \end{array}}\qquad\checkmark \end{array}

______


\large\begin{array}{l} \textsf{b) }\mathsf{(g\circ f)(-2)}\\\\ =\mathsf{g\big[f(-2)\big]}\\\\ =\mathsf{\sqrt{f(-2)}}\\\\ =\mathsf{\sqrt{(-2)^2-6\cdot (-2)+2}}\\\\ =\mathsf{\sqrt{4+12+2}}\\\\ =\mathsf{\sqrt{18}}\\\\ =\mathsf{\sqrt{3^2\cdot 2}}\\\\ =\mathsf{3\sqrt{2}}\\\\\\ \therefore~~\boxed{\begin{array}{c}\mathsf{(g\circ f)(-2)=3\sqrt{2}} \end{array}}\qquad\checkmark \end{array}

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If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2181559


\large\textsf{I hope this helps. :-)}


Tags: <em>composite function composition evaluate algebra</em>

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