Given:
Angle A = 18.6°
Angle B = 93°
Length of side AB = 646 meters
To find:
the distance across the river, distance between BC
Steps:
Since we know the measure of 2 angles of a triangle we can find the measure of the third angle.
18.6° + 93° + ∠C = 180°
111.6° + ∠C = 180°
∠C = 180° - 111.6°
∠C = 68.4°
Therefore the measure of angle C is 68.4°.
now we can use the law of Sines,
![BC[sin(68.4)] = 646 [sin(18.6)]](https://tex.z-dn.net/?f=BC%5Bsin%2868.4%29%5D%20%3D%20646%20%5Bsin%2818.6%29%5D)
meters
Therefore, the distance across the river is 222 meters.
Happy to help :)
If anyone need more help, feel free to ask
Answer:
1 13/28
Step-by-step explanation:
3×4/28 + 5×4/28. it 28 because the lcm of 4 and 7 is 28
21/28+20/28=41/28=1 13/28
It look like that.
Diameter = 2 so the radius = 1/2 * diameter = 1in
Volume of the cylinder = pi r^2 h
where h = height of the cylinder = 9 in
so volume = pi * 1^2 * 9 = 28.27 in^2 to nearest hundredth
Answer: Like the angles BAC (56°) and BDC has the same arc BC in the circumference, these angles must be congruent, then angle BDC must be equal to 56°.
Answer:think of many situations you can come up with or problems you can solve which will end up with the same answer if u use different methods
Step-by-step explanation:
