The mean score (rounded to 2 DP) in the Math's test for class B is 86.86.
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more numbers and variables.
Class A has 15 pupils and class B has 29 pupils. The mean score for class A is 55. Hence:
Mean score of A = (sum of all scores) / 15
55 = (sum of all scores) / 15
sum of all scores in A = 825
The mean score for both classes is 76. Hence:
[(sum of all scores in A) + (sum of all scores in B)]/(total number of pupils) = mean score of both classes
[825 + (sum of all scores in B)]/(15 + 29) = 76
sum of all scores in B = 2519
Mean score of B = (2519) / 29 = 86.86
The mean score (rounded to 2 DP) in the Math's test for class B is 86.86.
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Answer:
Let's define the cost of the cheaper game as X, and the cost of the pricer game as Y.
The total cost of both games is:
X + Y
We know that both games cost just above AED 80
Then:
X + Y > AED 80
From this, we want to prove that at least one of the games costed more than AED 40.
Now let's play with the possible prices of X, there are two possible cases:
X is larger than AED 40
X is equal to or smaller than AED 40.
If X is more than AED 40, then we have a game that costed more than AED 40.
If X is less than or equal to AED 40, then:
X ≥ AED 40
Now let's take the maximum value of X in this scenario, this is:
X = AED 40
Replacing this in the first inequality, we get:
X + Y > AED 80
Replacing the value of X we get:
AED 40 + Y > AED 80
Y > AED 80 - AED 40
Y > AED 40
So when X is equal or smaller than AED 40, the value of Y is larger than AED 40.
So we proven that in all the possible cases, at least one of the two games costs more than AED 40.
If parent functin is f(x)=|x|
it is moved to the left 2 units
vertically streched by a factor of 3
and moved up by 4 units in that order
because
to move a function to left c units, add c to every x
to vertically strech function by factor of c, multiply whole function by c
to move funciotn up c units, add c to whole function
so it is 2 to the left, verteically streched by a factor of 3 then moved up 4 units
