To find an outlier, multiply the IQR by 1.5
172,500 * 1.5 = 258,750
now, u add that to Q3.....545,000 + 258,750 = 803,750....anything above this number is an outlier
now,u subtract that from Q1....372,500 - 258,750 = 113,750....anything below that is an outlier
u have already done this...u have found the higher end and the lower end....so anyting larger then the higher end or lower then the lower end is ur outlier
so in ur data, there is only 1 outlier and that is 933.....130 is not an outlier because it is not less then 113,750.
To solve this you can make a perportion
252 x
----- = -----
350 100
and solve 252 times 100/350=72
252 is 72% of 350
No.
8 can be divided by 6 one more time. the correct answer should be 49 r2
<span>Area = (1/2)(533 ft)(525 ft) sin(53) = 111739 square feet</span>
I don't know if this is right or not but I think the coordinates at the angle on the circular protractor so for a) if you (114-62) you should get the answer, for b)if you (62+40) you should get the answer, for c) if you [114-(62+40)] you should get the answer.
