Slant height of tetrahedron is=6.53cm
Volume of the tetrahedron is=60.35
Given:
Length of each edge a=8cm
To find:
Slant height and volume of the tetrahedron
<u>Step by Step Explanation:
</u>
Solution;
Formula for calculating slant height is given as
Slant height=
Where a= length of each edge
Slant height=
=
=
=6.53cm
Similarly formula used for calculating volume is given as
Volume of the tetrahedron=
Substitute the value of a in above equation we get
Volume=
=
=
Volume=
=60.35
Result:
Thus the slant height and volume of tetrahedron are 6.53cm and 60.35
M<PLA = 1/2 m PYA
110 = 1/2 (12x - 20)
12x - 20 = 220
12x = 220 + 20 = 240
x = 240 / 12 = 20
Answer:
C
Step-by-step explanation:
Because nintendo price=300$
He has 215$
1 chore he does=7$
Meaning if he did 10 chores he get's 70$ added so he did 10 now he has 285$ If he does 2 more chores that is 14$ more added.
So he now has 299$ so he done 12 chores and he needs 1 more dollar so if he did 1 more he gets 306$ and that was the least amount of chores he could do if he wanted 300$
And there's your answer
Hope this helps have a awesome day:)
Answer:
c) Is not a property (hence (d) is not either)
Step-by-step explanation:
Remember that the chi square distribution with k degrees of freedom has this formula
Where N₁ , N₂m .... 
are independent random variables with standard normal distribution. Since it is a sum of squares, then the chi square distribution cant take negative values, thus (c) is not true as property. Therefore, (d) cant be true either.
Since the chi square is a sum of squares of a symmetrical random variable, it is skewed to the right (values with big absolute value, either positive or negative, will represent a big weight for the graph that is not compensated with values near 0). This shows that (a) is true
The more degrees of freedom the chi square has, the less skewed to the right it is, up to the point of being almost symmetrical for high values of k. In fact, the Central Limit Theorem states that a chi sqare with n degrees of freedom, with n big, will have a distribution approximate to a Normal distribution, therefore, it is not very skewed for high values of n. As a conclusion, the shape of the distribution changes when the degrees of freedom increase, because the distribution is more symmetrical the higher the degrees of freedom are. Thus, (b) is true.
