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avanturin [10]
3 years ago
5

I need help fast thanks

Mathematics
1 answer:
natka813 [3]3 years ago
3 0

Answer:

area - 16x+8

perimeter - 18x+8

Step-by-step explanation:

area:

1/2((8x+4)*4)

(4x+2)*4

16x+8

perimeter:

4x+2+8x+4+6x+2

18x+8

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3 years ago
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Please answer this question now in two minutes
Igoryamba

Answer: x=6, y=20

Step-by-step explanation:

Since ΔBCD and ΔTUS are congruent triangles, we can set the sides equal to each other.

y=2y-20                           [subtract both sides by 2y]

-y=-20                              [divide both sides by -1]

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3x+32=9x-4                    [add both sides by 4, and subtract both sides by 3x]

36=6x                              [divide both sides by 6]

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7 0
3 years ago
I can’t figure out, can someone please explain how to get the correct answer?
Karolina [17]

Answer:

  a)  CD = 9

  b)  AB = 20

Step-by-step explanation:

<h3>a)</h3>

In this geometry, all of the right triangles are similar. This means The ratio of short side to long side is the same for all of the triangles.

You are given the short and long sides of ΔADB, and the long side of ΔCDA. You are asked for the short side of ΔCDA, so you can write the proportion ...

  CD/AD = AD/BD

  CD/12 = 12/16

  CD = 12(12/16)

  CD = 9

__

<h3>b)</h3>

There are a couple of options for finding AD. One you may be familiar with is the Pythagorean theorem.

  AB² = AD² +DB²

  AB² = 12² +16² = 144 +256 = 400 . . . . fill in known values

  AB = √400 = 20 . . . . . take the square root

__

Alternatively, you can use the same proportional relationship that is described above. Here, we make use of the ratio of the hypotenuse to the long side.

  AB/BD = CB/AB

  AB² = BD·CB = 16·(16+9) = 16·25 . . . . cross multiply; fill in known values

  AB = √(16·25) = 4·5 . . . . . take the square root

  AB = 20

_____

<em>Additional comment</em>

This geometry, where the altitude of a right triangle is drawn, has some interesting properties. We have hinted at them above.

You can write three sets of proportions for this geometry: the ratios of short side and long side; the ratios of short side and hypotenuse; and the ratios of long side and hypotenuse. When you look at the way the sides touching the longest hypotenuse relate to that hypotenuse, you see three similar relations:

  AC = √(CD·CB)

  AD = √(DC·DB)

  AB = √(BD·BC) . . . . . . . . the relation used in part (b) above

This "square root of a product" is called the <em>geometric mean</em>. In effect, the length of a side touching the longest hypotenuse is the geometric mean of the two segments of that hypotenuse that it touches.

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2 years ago
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Answer:

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Answer:

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