All categories

3 years ago

For x= 2, what is the value of the expression in the box? The expression is 3.6 divided by x A. 1.6 B.18 C.0.18 D.1.8

Mathematics

1 answer:

Ostrovityanka [42]3 years ago

6 0

Answer:

please give me brainiest

Step-by-step explanation:

algebraic Expressions Calculator. An online algebra calculator simplifies expression for the input you given in the input box. If you feel difficulty in solving some tough algebraic expression, this page will help you to solve the equation in a second.

You might be interested in

I really need help with this question

jenyasd209 [6]

Answer:

its a discrete graph

Step-by-step explanation:

hope this helps

5 0

3 years ago

How many radians is 340 degrees

MakcuM [25]

Answer:

About 5.93412 radians.

Step-by-step explanation:

To calculate it you would multiply 340 by π/180 because if graphed, 340 degrees is located in the first quadrant.

I hope this helps! :)

5 0

3 years ago

Read 2 more answers

What is 14/26 simplified?

Reika [66]

14/26 simplified is 7/13

4 0

3 years ago

WORD PROBLEMS

kotegsom [21]

Answer:

The answer is

Step-by-step explanation:

Step by step

3 0

3 years ago

Use mathematical induction to prove the statement is true for all positive integers n, or show why it is false:

kondaur [170]

$\text{Proof by induction:}$
$\text{Test that the statement holds or n = 1}$

$LHS = (3 - 2)^{2} = 1$
$RHS = \frac{6 - 4}{2} = \frac{2}{2} = 1 = LHS$
$\text{Thus, the statement holds for the base case.}$

$\text{Assume the statement holds for some arbitrary term, n= k}$
$1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2} = \frac{k(6k^{2} - 3k - 1)}{2}$

$\text{Prove it is true for n = k + 1}$
$RTP: 1^{2} + 4^{2} + 7^{2} + ... + [3(k + 1) - 2]^{2} = \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2} = \frac{(k + 1)[6k^{2} + 9k + 2]}{2}$

$LHS = \underbrace{1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2}}_{\frac{k(6k^{2} - 3k - 1)}{2}} + [3(k + 1) - 2]^{2}$
$= \frac{k(6k^{2} - 3k - 1)}{2} + [3(k + 1) - 2]^{2}$
$= \frac{k(6k^{2} - 3k - 1) + 2[3(k + 1) - 2]^{2}}{2}$
$= \frac{k(6k^{2} - 3k - 1) + 2(3k + 1)^{2}}{2}$
$= \frac{k(6k^{2} - 3k - 1) + 18k^{2} + 12k + 2}{2}$
$= \frac{k(6k^{2} - 3k - 1 + 18k + 12) + 2}{2}$
$= \frac{k(6k^{2} + 15k + 11) + 2}{}$
$= \frac{(k + 1)[6k^{2} + 9k + 2]}{2}$
$= \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2}$
$= RHS$

Since it is true for n = 1, n = k, and n = k + 1, by the principles of mathematical induction, it is true for all positive values of n.

3 0

3 years ago