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aev [14]
3 years ago
15

What happens if simultaneous Equations have two of the same variable like below? How would I solve it?

Mathematics
1 answer:
hoa [83]3 years ago
4 0

Answer:

C = 20

Step-by-step explanation:

What happens if simultaneous Equations have two of the same variable like below? How would I solve it?

6A + 4B + 5C = 390

6A + 4B + 5.75C = 405​

Step 1

We solve for C first

6A + 4B + 5C = 390....Equation 1

6A + 4B + 5.75C = 405​... Equation 2

We substract Equation 1 from Equation 2

0.75C = 15

C = 15/0.75

C = 20

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Answer with explanation:

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If there are 360 grams of radioactive material with a half-life of 8 hours, how much of the radioactive material will be left af
lyudmila [28]

Answer:

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Step-by-step explanation:

A half-life is how long it takes for half of the amount to go away. In this case, we see that we have two half-life periods worth, which you can determine by dividing the total time by the half-life time.

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