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Kruka [31]
3 years ago
9

Please answer A and B!!!

Mathematics
1 answer:
erik [133]3 years ago
6 0

Answer:

7 and 2

Step-by-step explanation:

i did this before i know

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Use the distributive property to factor the expression
Naily [24]

Answer:

5(x^2 + 5)

Step-by-step explanation:

The binomial 5х^2 + 25 has the factor 5 in each term.  Thus, in factored form, 5х^2+ 25  = 5(x^2 + 5).

5 0
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19 divided by $70.49=
andrew-mc [135]
The answer is 3.71 i did the math and it was the correct answer for it
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Help with the question below
katovenus [111]
D is the only viable answer among these, as A, B, and C all contain two even integers which, by definition, have a greatest common factor of 2.

<em>Correction: </em>I was incorrect in saying that <em>all </em>even integers have a greatest common factor of 2; 2 is at least guaranteed to be <em>one of the common factors </em>in any group of even numbers, but these examples all have it as their <em>greatest </em>common factor as well.
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3 years ago
A square has a perimeter of 36 cm. What is the length of each side?​
shepuryov [24]

Answer:

a square has all its sides equal so you divide by 4

to get 9cm

<h3> hope it helps!</h3>

6 0
3 years ago
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2x-y=-1 , 3x-y=2 solve by substition
Mazyrski [523]

Answer:

x = 3, y = 7

or (3,7)

Step-by-step explanation:

We are given the system of equations below:

\large{ \begin{cases} 2x - y =  - 1 \\ 3x - y = 2 \end{cases}}

We are required to solve the system by substitution method. What we have to do is to isolate either x-term or y-term so we can use the method. I will be isolating y-term because it is faster due to having 1 as a coefficient.

By isolating y-term, just pick one of the given equations to isolate. No need to isolate the whole system. (I will be isolating y-term of the first equation.)

\large{ \begin{cases} y=  2x + 1\\ 3x - y = 2 \end{cases}}

Then we substitute y = 2x+1 in the second equation.

\large{3x - (2x + 1) = 2}

Use the distribution property.

\large{3x - 2x - 1 = 2}

Isolate x-term to solve the equation.

\large{x = 2 + 1} \\  \large{x = 3}

Since we are solving a system of equations. We have to solve for both x-value and y-value to complete. We have already found x-value, but nor y-value yet. Therefore, our next step is to substitute the value of x that we solved in any given equations. It's recommended to substitute in an equation that doesn't have high coefficient value. So I will be substituting x = 3 in the first equation.

\large{2x - y =  - 1}  \\  \large{2(3) - y =  - 1} \\  \large{6 - y =  - 1}

Isolate and solve for y-term.

\large{6 + 1 = y} \\  \large{7 = y} \\  \large{y = 7}

Since we substitute x = 3 and get y = 7. We can write in ordered pairs as (3,7)

Hence, the solution is (3,7)

7 0
3 years ago
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