Given a quadratic equation in standard form
The discriminant D
tells the types of roots the equation has.
In this case, we have
Then, the discriminant of this quadratic equation will be
Finally, the value of discriminat is 49 and as he discriminant is greater than zero then this quadratic equation has 2 different real solutions.
<span>
y = 7 + 3/5
y = 35/5 + 3/5
y = 38/5
y = 2*(38/5)
y = 76/10
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lunch time:
z = 1/2
z = 5*(1/2)
z = 5/10
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time switching classes:
w = 7/10
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y - 6x - z - w = 0
6x = y - z - w
x = (y - z - w)/6
x = (76/10 - 5/10 - 7/10)/6
x = (76 - 5 - 7)/(10*6)
x = (64)/(10*6)
x = (2*2*2*2*2*2)/(2*5*2*3)
x = (2*2*2*2)/(5*3)
x = 16/15
x = 1.0666666666
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check:
y = 7 + 3/5
y = 7.6
z = 1/2
z = 0.5
w = 7/10
w = 0.7
y - 6x - z - w = 0
6x = y - z - w
x = (y - z - w)/6
x = (7.6 - 0.5 - 0.7)/6
x = 1.0666666666
answer:
1.07 hours</span>
Answer:
6
Step-by-step explanation:
3x+6+5x+10=64
3x+5x+6+10=64
8x+16=64
8x=64-16
8x=48
divide both sides by 8
x=6
Answer:
x = 1/2
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
Step 2: Subtract 2 from both sides.
Step 3: Divide both sides by -4.
Hello:
x²+3x-2 = 0
delta = b²-4ac a=1 b = 3 c = -2
delta =(3)²-4(1)(-2) =17 =(<span>√17)²
</span><span>x = −3±√17/2</span>
