20.if m <6=72, then m < 7=108
21. if m<8,then m<7=80
22.if m<110,then m<6=90
23.if m<123, then m<8=123
24.if m<142, then m<7=38
25.if m<13, then m<8=167
26.if m<170, then m<10
27.if m<26, then m <154
,
Given:
n = 20, sample size
xbar = 17.5, sample mean
s = 3.8, sample standard deiation
99% confidence interval
The degrees of freedom is
df = n-1 = 19
We do not know the population standard deviation, so we should determine t* that corresponds to df = 19.
From a one-tailed distribution, 99% CI means using a p-value of 0.005.
Obtain
t* = 2.8609.
The 99% confidence interval is
xbar +/- t*(s/√n)
t*(s/√n) = 2.8609*(3.8/√20) = 2.4309
The 99% confidence interval is
(17.5 - 2.4309, 17.5 + 2.4309) = (15.069, 19.931)
Answer: The 99% confidence interval is (15.07, 19.93)
Answer:

Step-by-step explanation:
To solve this problem, we can use the area of a circle formula:

<em>A = area</em>
<em>r = radius</em>
Lets plug the values into the equation:
Calculate 
Multiply
and 9 together

The area of the truck wheel is 
Answer:

Step-by-step explanation:
As the mean is 20.2 and the standard deviation is 2.4
The range within the first standard deviation is
(17.8,22.6)
This means that we can safely use the range of (18,22) as we cannot confirm whether the other values fall within the range.
Within this range there are
