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Mathematics

1 answer:

blagie [28]3 years ago

3 0

I believe the answer should be 4 and 2

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Solve for z<br> -p(d+z) = -2z+59−p(d+z)=−2z+59

alexira [117]

$-p(d+z)=-2z+59\qquad\text{use distributive property}\\\\-pd-pz=-2z+59\qquad\text{add pd to both sides}\\\\-pz=-2z+pd+59\qquad\text{add 2z to both sides}\\\\2z-pz=pd+59\\\\z(2-p)=pd+59\qquad\text{divide both sides by}\ (2-p)\neq0\\\\\boxed{z=\dfrac{pd+59}{2-p}}$

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3 years ago

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Sav [38]

The first one question 17 is W

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3 years ago

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If there are 132 stamps on a total of 12 pages in a collector's book, what the unit rate of stamps per page ?

DanielleElmas [232]

Answer: 11 stamps per page

Step-by-step explanation: 132 divided by 12

4 0

3 years ago

Lin’s teacher uses a box to store her set of cubes with an edge length of 1/2 inch if the box is completely full how many cubes

Sauron [17]

Answer:
448 cubes
Step-by-step explanation:
Volume of cubes fitted in the box will be equal to the cumulative volume of the cubes.
Since, volume of a cube = (Side)³
Side of the cube = 1/2 inch
Therefore, volume of the cube = (1/2)3=1/8 inches
Volume of the storage box = 56 cubic inches
Since, number of cubes fitted in the storage box
= 56/1/8
= 56 × 8
= 448 cubes
Therefore, number of cubes fitted in the storage box = 448

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3 years ago

The incubation time for hummingbird eggs is approximately normal and has a mean of 16 days and standard deviation of 2 days. Let

Veseljchak [2.6K]

Answer:

0.5328 = 53.28% probability that the length of hatching times is between 15 and 18 days.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 16 days and standard deviation of 2 days.

This means that $\mu = 16, \sigma = 2$