Hello,
(6x+13)+(3x-4)=180
9x+9=180
9x=171
x=19
angle QRS measures 3x-4=3*19-4=53(°)
A) Diagram
Below is a sketch of the recctangular lawn (the inside rectangle) and the gravel border.
6 ft + 150 yards + 6 ft
-------------------------------
| |
| --------------------- |
| | | |
| | | | 6 ft + 80 yard + 6 ft
| | | |
| --------------------- |
| |
|------------------------------|
B) How many square feet of the gravel will surround the lawn?
Conversion: 1 yard = 3 feet
=> 80 yard = 80*3 feet = 240 feet
=> 150 yard = 150 * 3 feet = 450 feet
Area of the external rectangle = (6 ft + 240 ft + 6 ft) (6 ft + 450 ft + 6 ft) = 252 ft * 462 ft = 116,424 ft^2
Area of the internal rectangle = 240 ft * 450 ft = 108,000 ft^2
Area of the gravel border = 116,424 ft^2 - 108,000 ft^2 = 8424 ft^2
answer: 8424 ft^2
C) volume
volume = area of the base * depth
2 inches = 2/12 ft = 1/6 ft
=> volume = 8424 ft^2 * 1/6 ft = 1404 ft^3
answer: 1404 ft^3
C) cost
1 yard^3 = $ 30
1yard ^3 = (3 feet)^3 = 27 ft^3
=> cost = $ 30 / 27 ft^3
=> 1404 ft^3 * $30 / 27 ft^3 = $ 1560
answer: $ 1560
It is just asking you what the y-value is when x=6. In this case it is about 2.5
Answer:
21.3188kg or 21.3kg
Step-by-step explanation:
As one kilogram is equal to 2.20462 pounds we can calculate the weight in kilograms by taking 2.20462 / 47 and we get 21.3188kg
Multiply the first equation by -1 and add it to the second one, getting
y-4z=-10
Multiply the first equation by 2 and add it to the third one, getting -2y+10z=26
As you can see, we eliminated x and turned it into two equations with 2 variables.
Multiply the first new equation by 2 and add it to the second one to get
2z=6 and z=3. Substitute it in to -2y+10z=26 to get y=2 and substitute it into <span>-x+y+z=4 to get x=1</span>
