So... our numbers... let's say the first one is hmmm "a"
so the second and subsequent are
a
a+1
a+2
a+3
a+4
there, 5 consecutive whole numbers or integers for that matter
now, we know the sum of the square of the first three,
is the same as the sum of the square of the last two
so

do a binomial theorem expansion on those, solve for "a"
His work should have looked like this.
2x + y = 5
x − 2y = 10
y = 5 − 2x
x − 2(5 − 2x) = 10
x − 10 + 4x = 10
5x − 10 = 10 When he added in both sides, he subtracted 10 from 10,
5x = 20 instead of adding 10 from 10 to make 20.
x = 4
2(4) + y = 5
8 + y = 5
y = -3
Answer:
4
Step-by-step explanation:
Equation:-
2(5-3)
=> 2(2)
=> 4
Answer:
a
Step-by-step explanation:
this because it is what it is and therefore henceforth ergo this is correct so according to ir doubt i feel like u are really smart
Answer: y=2
Step-by-step explanation:
Distribute the numbers -2 and 3...
6y-2y-2=3y-6+6
The -6 and 6 cancel each other out...
6y-2y-2=3y
Combine like terms....
4y-2=3y
Move 4y over....
-2=-y
Multiply both sides by -1.....
2=y
That’s your solution! Hope this helps!