Answer: flog6e
Step-by-step explanation:
The power property of logarithm rule is :
Logamn = nlogaM
Applying the logarithm of power rule in the given expression we have:
Log6eF= flog6e
The second option that is flog6e is the right option among all the given options.
Thats it option (C). Hope it helps!!
When you have something like this, all you need to do is substitute the values, the last is for what value of x
For the first one;
((x^2+1)+(x-2))(2)
(x^2+x-1)(2)
(2)^2+(2)-1
4+2-1
5
For the second one;
((x^2+1)-(x-2))(3)
(x^2-x+3)(3)
(3)^2-(3)+3
9-3+3
9
For the last one;
3(x^2+1)(7)+2(x-2)(3)
3((7)^2+7)+2((3)-2)
3(49+7)+2(3-2)
3(56)+2(1)
168+2
170
<em>2x - 5 + 3x = 35
</em>
<em>simplify
</em>
<em>5x - 5 = 35
</em>
<em>add 5 to both sides
</em>
<em>5x - 5 + 5 = 35 + 5
</em>
<em>simplify
</em>
<em>5x = 40
</em>
<em>divide both sides by 5
</em>
<em>5x/5 = 40/5
</em>
<em>simplify
</em>
<em>x = 8
</em>
<em>
</em>
<em />
15% of 425
(15/100) * 425
(3/20) * 425
(3/4) * 85
255 / 4
63.75
