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UkoKoshka [18]
3 years ago
13

Can someone please help me?

Mathematics
1 answer:
Ne4ueva [31]3 years ago
5 0

9514 1404 393

Answer:

  • x = 6
  • y = 55

Step-by-step explanation:

Angles opposite congruent sides are congruent, so base angles D and F of this isosceles triangle have the same measure:

  y = 55

__

The sum of angles in the triangle is 180°, so ...

  55° +(11x +4)° +55° = 180°

  11x = 66 . . . . . . . . divide by °, subtract 114

  x = 6 . . . . . . . . . . .divide by 11

The values of x and y are 6 and 55, respectively.

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Rosemary is driving to Chicago, and she is 84 miles away. She wants to arrive in 1.5 hours. What rate of speed will she have to
vagabundo [1.1K]

Answer:

56 mph

Step-by-step explanation:

Process of elimination. 126 mph is much too high because it's more than the distance and they will arrive too early. 65 + 65 ÷ 2 = 97.5, that's more than 84 miles. The reason we divide by 2 is because of the .5. Now all we have is 56 mph. To check, 56 + 56 ÷ 2 = 84

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2 years ago
Clifford is paid $4.25 per hour plus time and a half on holidays and makes an average of 21% tips on his food sales as a server
maks197457 [2]
4.25(15)+4.25(1.5)(7)+0.21(1345)=
63.75+44.625+282.45=$390.825
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3 years ago
What 34 divided by 20196
Komok [63]

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0.00168350168

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I am learning about estimating quotients using multiples. 188 divided by 5 =
Dmitriy789 [7]

Answer:

37.6

Step-by-step explanation:

8 0
3 years ago
Help me Please....................
MakcuM [25]

9514 1404 393

Answer:

  1.3363

Step-by-step explanation:

The basic idea here is to find an expression for the direction vector between a point on L1 and a point on L2. Then, solve for the points on L1 and L2 that make that vector perpendicular to both lines L1 and L2. (The dot product of direction vectors is zero.) The distance between the points found is the shortest distance between the lines.

__

Let P be a point on L1. Then the parametric equation for P is ...

  P = (6t, 0, -t) . . . . . . origin + t × direction vector

Let Q be a point on L2. The direction vector for L2 is given by the difference between the given points. It is (4-1, 1-(-1), 6-1) = (3, 2, 5). Then the parametric equation for Q is ...

  Q = (3s+1, 2s-1, 5s+1) . . . . (1, -1, 1) + s × direction vector

The direction vector for PQ is ...

  Q -P = (3s+1-6t, 2s-1, 5s+1+t)

The dot product of this and the two lines' direction vectors will be zero:

  (3s+1-6t, 2s-1, 5s+1+t)·(6, 0, -1) = 0 = 13s -37t +5 . . . perpendicular to L1

  (3s+1-6t, 2s-1, 5s+1+t)·(3, 2, 5) = 0 = 38s -13t +6 . . . perpendicular to L2

The solution to these equations is ...

  s = -157/1237

  t = 112/1237

Then (Q-P) becomes (94, -1551, 564)/1237, and its length is ...

  |PQ| = √(94² +1551² +564²)/1237 ≈ 1.3363

The distance between the two lines is about 1.3363 units.

8 0
3 years ago
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