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seropon [69]
3 years ago
5

Can you help me pls 6+2=

Mathematics
1 answer:
tankabanditka [31]3 years ago
6 0

Answer:

The answer is 8

Step-by-step explanation:

6+2=8

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Write the equation 2x-3y=6in slope -intercept form​
Tcecarenko [31]

Answer:

y = 2/3 x -2

Step-by-step explanation:

Slope intercept form is y = mx+b where m is the slope and b is the y intercept

We need to solve for y

2x-3y = 6

Subtract 2x from each side

2x-2x-3y=-2x+6

-3y = -2x+6

Divide  by -3

-3y/-3 = -2/-3x+6 /-3

y = 2/3 x -2

The slope is 2/3 and the y intercept is -2

7 0
3 years ago
dave picked 1/5 of a pound strawberries.that afternoon daves sister ate 4/5 of the strawberries.how many pounds of strawberries
Yanka [14]

Answer:

I dont know but If that was my sister she would be dead

Step-by-step explanation:

7 0
3 years ago
Nick has 189 trading cards. Kyle has 198 trading cards. Who has fewer cards ?
Darya [45]
Nick has fewer trading cards. 189 < 198; there is a difference of 9.
7 0
4 years ago
Read 2 more answers
Consider the function on the interval (0, 2π). f(x) = sin x + cos x (a) Find the open intervals on which the function is increas
Annette [7]

Answer:Increasing in x∈(0,π/4)∪(5π/4,2π) decreasing in(π/4,5π/4)

Step-by-step explanation:

given f(x) = sin(x) + cos(x)

f(x) can be rewritten as \sqrt{2} [\frac{sin(x)}{\sqrt{2} }+\frac{cos(x)}{\sqrt{2} }  ]..................(a)\\\\\ \frac{1}{\sqrt{2} } = cos(45) = sin(45)\\\\

Using these result in equation a we get

f(x) = \sqrt{2} [ cos(45)sin(x)+sin(45)cos(x)]\\\\= \sqrt{2} [sin(45+x)]..........(b)

Now we know that for derivative with respect to dependent variable is positive for an increasing function

Differentiating b on both sides with respect to x we get

f '(x) = f '(x)=\sqrt{2}  \frac{dsin(45+x)}{dx}\\ \\f'(x)=\sqrt{2} cos(45+x)\\\\f'(x)>0=>\sqrt{2} cos(45+x)>0

where x∈(0,2π)

we know that cox(x) > 0 for x∈[0,π/2]∪[3π/2,2π]

Thus for cos(π/4+x)>0 we should have

1) π/4 + x < π/2  => x<π/4  => x∈[0,π/4]

2) π/4 + x > 3π/2  => x > 5π/4  => x∈[5π/4,2π]

from conditions 1 and 2 we have  x∈(0,π/4)∪(5π/4,2π)

Thus the function is decreasing in x∈(π/4,5π/4)

5 0
3 years ago
Find the zero places of the quadratic function: y= x^2 + 5x + 6
andre [41]

The required zero places of the given equation  y= x² + 5x + 6 is x = -2 and x = -3.

Given that,
An equation   y= x² + 5x + 6,
To determine the Zeros of the equation given above.

<h3>What is the equation?</h3>

The equation is the relationship between variables and is represented as y =ax + b is an example of a polynomial equation.

Here, given equation is, y= x² + 5x + 6
Now, let y = 0
x² + 5x + 6 = 0
x² + 2x + 3x + 6 = 0
x(x + 2) + 3 (x + 2) = 0
(x + 2) * (x + 3) = 0
x + 2 = 0    ;   x + 3 = 0
x = -2  and x = -3

Thus, the required zero places of the given equation  y= x² + 5x + 6 is x = -2 and x = -3.

Learn more about the equation here:

brainly.com/question/10413253

#SPJ1


8 0
2 years ago
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