If a = -4, then what is the value of -a? OA. 5 OB. 4 OC. 0 OD D. -4

Consider a circle whose equation is x2 + y2 – 2x – 8 = 0. Which statements are true? Select three options. The radius of the cir

FromTheMoon [43]

The statements which are correct about the equation of circle $x^{2} +y^{2}-2x-8=0$ are 1) The radius of the circle is 3 units,2) The center of the circle lies on the x axis,5) The radius of this circle is the same the radius of the circle whose equation is $x^{2} +y^{2} =9$ .

Given the equation of circle be $x^{2} +y^{2}-2x-8=0$ .

We are required to find the appropriate statements related to the equation $x^{2} +y^{2}-2x-8=0$ .

$x^{2} +y^{2}-2x-8=0$ can be written as under:

$x^{2} +y^{2} -2x+1-9=0$

$x^{2} +1^{2}-2x+y^{2} -9=0$

$(x-1)^{2}+y^{2}$ -9=0

$(x-1)^{2} +y^{2} =9$

$(x-1)^{2}+y^{2} =3^{2}$

Equation of a circle usually in the form $x^{2} +y^{2} =a^{2}$ in which a is radius.

From the comparison of both the equations we get that radius is 3 units.

From the equation point will be (1,0). It is on the x axis.

Hence the statements which are correct about the equation of circle $x^{2} +y^{2}-2x-8=0$ are 1) The radius of the circle is 3 units,2) The center of the circle lies on the x axis,5) The radius of this circle is the same the radius of the circle whose equation is $x^{2} +y^{2} =9$ .

Learn more about radius at brainly.com/question/24375372

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1 year ago

What is the y-intercept of the exponential function? f(x)=−32(2)x−3+3 Enter your answer in the box.

Bogdan [553]

y-intercept for x = 0.

Substitute x = 0 to the equation of the function:

$f(x)=-32(2)^{x-3}+3\\\\f(0)=-32(2)^{0-3}+3=-32(2)^{-3}+3=-32\cdot\dfrac{1}{2^3}+3=-32\cdot\dfrac{1}{8}+3\\\\=-4+3=-1\\\\Answer:\ \boxed{y-intercept=-1\to(0,\ -1)}$