3 years ago

PLEASE HELP!

Mathematics

1 answer:

REY [17]3 years ago

7 0

Y = -5/7 is the slope

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What is the phase of y= -3cos (3x-pi) +5

ratelena [41]

Answer:

$- \frac{\pi}{3}$

Step-by-step explanation:

Given

$y = -3\cos(3x - \pi) + 5$

Required

The phase

We have:

$y = -3\cos(3x - \pi) + 5$

Rewrite as:

$y = -3\cos(3(x - \frac{\pi}{3})) + 5$

A cosine function is represented as:

$y = A\cos(B(x + C)) + D$

Where:

$C \to$ Phase

By comparison:

$C = - \frac{\pi}{3}$

Hence, the phase is: $- \frac{\pi}{3}$

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2 years ago

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Answer:

29.04

Step-by-step explanation:

Multiply: 120*.242=29.04

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2 years ago

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Link l = m = parallel

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What value of h makes the statement true? (17+h)+(–9) = 17+(5+(–9))

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2 years ago

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