Answer:
The tall parent was heterozygous
Explanation:
If tall height is dominant to short height the only genotype possible for short height is hh, while there are two possible genotypes for tall height, Hh and HH. When HH is crossed with hh all the offspring are Hh, but if Hh is crossed with hh, a quarter of the offspring is HH, a quarter is hh and half is Hh. If the tall pea plants were HH there would only be tall offspring, but because there are some short offspring we know that the tall pea plants must have a genotype of Hh.
Answer:
The waste products are Carbon Dioxide and Water.
Explanation:
<span>Substances can move into and out of cells through the cell membrane. The three main types of movement are diffusion, osmosis and active transport.</span>
The right option is; A. Prokaryotic cells have a nucleus
''Prokaryotic cells have a nucleus'' is the statement about prokaryotic cells that is NOT true.
Prokaryotic cells are cells that lack a true nucleus and some other cell organelles. Prokaryotic cells are found in unicellular organisms called prokaryotes. Examples of prokaryotes are; Bacteria and Archaea. The components of prokaryotic cells include plasma membrane, cell wall, cytoplasm, nucleoid, ribosomes, DNA (deoxyribonucleic acid). Most of the prokaryotic’s DNA (genetic material) is located in a middle area of the cell (nucleoid), and it contains a single large loop known as a circular chromosome.
Exactly 989527/1048576, or approximately 94.37%
Since each trait is carried on a different chromosome, the two traits are independent of each other. Since both parents are heterozygous for the trait, each parent can contribute 1 of a possible 4 combinations of the alleles. So there are 16 possible offspring. I'll use "a", "A", "b", "B" to represent each allele and the possible children are aabb, aabB, aaBb, aaBB, aAbb, aAbB, aABb, aABB, Aabb, AabB, AaBb, AaBB, AAbb, AAbB, AABb, and AABB
Of the above 16 possibilities, there are 7 that are homozygous in an undesired traint and 9 that don't exhibit the undesired trait. So let's first calculate the probability of "what are the chances that all 5 children not exhibiting an undesired trait?" and then subtract that result from 1. So
1-(9/16)^5 = 1 - 59049/1048576 = 989527/1048576 which is approximately 0.943686485 = 94.3686485%
So the answer is exactly 989527/1048576, or approximately 94.37%
